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How would you sketch y = xsecx? (1 Viewer)

Templar

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Sketch y=x, y=Sec[x] on one graph and multiply them together.
 

Riviet

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Hehe, easier said than done, it's hard to determine where the curves intersect, so you'll need to multiply several ordinates together and see what the shape of the curve is from the points you plot.
 

tutor01

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If the question permits, I would use Calculus to help get an idea of the shape of the curve.

See attached.

The curve will have maxima and minima similar to the graph of y=secx except the branches will get increasingly further from the x-axis for larger values of x. The branches will also not be perfectly symmetrical.

Note also that the graph will have point symmetry about the origin. It's an odd function.
 

Riviet

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Mumma said:
A(ax,ay) * B(bx,by) = C(axbx,ayby) ? i guessed
Yep, you got the idea. ;)
The important parts of the graph to look for are when the curves cross the lines y=+1 as well as x-intercepts of either curve as these points are easiest to plot.
 
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pLuvia

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One more thing use y=1 and y=-1 as a point that it always crosses
 

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