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HSC 2013 Maths Marathon (archive) (1 Viewer)

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nightweaver066

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Re: HSC 2013 2U Marathon

edit:accidently posted a 3u question
 
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anomalousdecay

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Re: HSC 2013 2U Marathon

are u mocking me?
No. I was just trying to encourage 2-unit students to try this out. Even 3-unit students are welcome, as long as they don't use substitution.

But 4-unit students should leave this for others.
 

anomalousdecay

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Re: HSC 2013 2U Marathon

Yay. We have someone here. You can look at my harder 2-unit question on the 3-unit marathon. You will like it omgiloverice.

Using the standards integrals table, find in simplest possible form:

 

omgiloverice

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Re: HSC 2013 2U Marathon











Now somebody answer my question on the 3 unit thread and previous question on here
 

omgiloverice

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Re: HSC 2013 2U Marathon

omg finally......... somebody from 2U, and useful tip use spaces~


 
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Trebla

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Re: HSC 2013 2U Marathon

Solve simultaneously:

2a + 3b = 11
2c + 3d = 24
3a - 2b - 3c + 2d = 0
a + 3b + 3c + 6d - ac - bd = 21

The solutions are quite nice if you can handle it.
 
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omgiloverice

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Re: HSC 2013 2U Marathon






















Good question stumped me for a good few minutes~
 
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braintic

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Re: HSC 2013 2U Marathon

For a given function f(x), we know that f(1)=3, f(3)=-2, f(6)=5, f ' (1)=f ' (3)=f ' (6)=0, and f '' (x) > 0 for 2 < x < 4, and -ve elsewhere.

Find the area of the region bounded by y=f ' (x) and the x-axis.

[Do not attempt to fit an equation to f(x) or any of its derivatives]
 
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