Sy123
This too shall pass
- Joined
- Nov 6, 2011
- Messages
- 3,730
- Gender
- Male
- HSC
- 2013
Re: HSC 2013 4U Marathon
WLWLWLWLWLWLWLWLWLWLWLWLWLWLWLWLWLWLWL WWWWW WWWWW and then win.
And this can go on infinitely many times, so infinite series are involved. I was experimenting with $2, whether he wins up to 4.
When he has $2, (also I made probability p so its easier), I seperated each decision into two groups, so each game he plays will have a structure like:
(WL) , (WL) , (LW) , (WL) , .... (WL) , (WW).
It doesn't matter what order the L and W's are after each partition, so the probability is
So yeah this might help some other people in trying to find the answer to the problem.
But for example, if we denote W as win, and L as Loss, he can go:Yeah that makes more sense.
So then would it be......
a)
P($20) = 10C0 (18/37)^10(19/37) + 10C1(18/37)^11(19/37) + 10C2(18/37)^12(19/37)^2 + 10C3(18/37)^13(19/37)^3 +10C4(18/37)^14(19/37)^4 + 10C5(18/37)^15(19/37)^5 + 10C6(18/37)^16(19/37)^6 +10C7(18/37)^17(19/37)^7 + 10C8(18/37)^18(19/37)^8 + 10C9(18/37)^19(19/37)^9
P($0) = 1- P($20)
b) If he makes a single bet with his money, he will have a higher probability of winning.
However, he has a higher probability of losing as well.
If he only wants to make a few dollars, it is better for him to bet $1 at a time.
If he only wants double-or-nothing then he must do it all in one bet.
?????? For some reason I am thinking that I missed something again .
WLWLWLWLWLWLWLWLWLWLWLWLWLWLWLWLWLWLWL WWWWW WWWWW and then win.
And this can go on infinitely many times, so infinite series are involved. I was experimenting with $2, whether he wins up to 4.
When he has $2, (also I made probability p so its easier), I seperated each decision into two groups, so each game he plays will have a structure like:
(WL) , (WL) , (LW) , (WL) , .... (WL) , (WW).
It doesn't matter what order the L and W's are after each partition, so the probability is
So yeah this might help some other people in trying to find the answer to the problem.
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