HSC 2013 MX2 Marathon (archive) (6 Viewers)

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anomalousdecay

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Re: HSC 2014 4U Marathon

We needed a new LaTex renderer because of the problems we experienced before.

So inevitably the font changed!
 

seanieg89

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Re: HSC 2014 4U Marathon

These type of questions aren't even in the four unit syllabus are they? I mean I have no idea how to even to begin attempting this problem.
Well, they only aren't in the syllabus in the sense that some of them are harder than any question the bos would set in an actual HSC paper.

They don't need any theory from outside the mx2 course to do.
 

Sy123

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Re: HSC 2014 4U Marathon

Let f be a real-valued function defined on R. For which values of the real constant p does the inequality below imply that f is twice differentiable?

|f(x)-f(y)| =< C|x-y|^p for all x,y. C a constant.

Justify your answer with proof.
Just checking, but is the answer p=2?
 

Sy123

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Re: HSC 2014 4U Marathon



In case latex is down it is asking to prove:

(n!)^(1/n) <= ((n+1)!)^(1/(n+1))

for positive integral n
 

Sy123

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Re: HSC 2014 4U Marathon

A (2 dimensional) ball with radius 'r' has a fixed red marker on it. It is rolled along the flat ground and the red marker leaves a trail in the air.
If the ball was initially above the origin with the marker being at the origin. Find the Cartesian equation describing the path of the marker.
 

seanieg89

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Re: HSC 2014 4U Marathon

Just checking, but is the answer p=2?
p=2 is not quite good enough to get second differentiability (consider f(x)=x^3/|x|, f(0)=0. this func is not twice diffble at 0, yet obeys the p=2 bound), (also, there is more than value of p that works).
 

vafa

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Re: HSC 2014 4U Marathon

These type of questions aren't even in the four unit syllabus are they? I mean I have no idea how to even to begin attempting this problem.
Hint: Use the fundamental theorem of calculus: a polynomial of degree n, has n roots. Let set A be all the roots and let set B be A-1. From that you can see that B^2 is always a root. If B is a complex number and its modulus is bigger than one, you get an infinite number of solutions; this can not happen because you only should have n roots. If the modulus of that complex number is between 0 and 1 same thing happens therefore that the modulus has got to be 0 or 1 and continue this logic ...
 

braintic

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Re: HSC 2014 4U Marathon

A (2 dimensional) ball with radius 'r' has a fixed red marker on it. It is rolled along the flat ground and the red marker leaves a trail in the air.
If the ball was initially above the origin with the marker being at the origin. Find the Cartesian equation describing the path of the marker.
The red marker has me stumped. But I think I can do it if it is green.
 

Sy123

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Re: HSC 2014 4U Marathon

 
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seanieg89

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Re: HSC 2014 4U Marathon



Hint: Induction is one way to do this.
 
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