It is because if they share the same center and are tangents then the semi major or semi minor is equal to the radius. The value of the semi minor/semi major axis gives the distance from the center to the point. Therefore if they share the same center and the circle has a radius equal to the semi major or semi minor axis it is a tangent at both sides of the axis. Can't explain it D:
Start up a forum where you just post random Latex thats how me and ekman learnt it and i think usinng logic is more simpler than calculations for thisHopefully, this suffices (still no LATEX):
http://i.imgur.com/QJNbrGy.jpg?1
Couple of fixes:
*r is the length of the semi-major/semi-minor axis (in final answer)
*gradients are equal
That is sufficient to prove that if the radius and the one of the axes of the ellipse were equal, then they are tangent to each other. However the question is asking, given that they are tangent, that therefore the radius and one of the axes are equal.It is because if they share the same center and are tangents then the semi major or semi minor is equal to the radius. The value of the semi minor/semi major axis gives the distance from the center to the point. Therefore if they share the same center and the circle has a radius equal to the semi major or semi minor axis it is a tangent at both sides of the axis. Can't explain it D:
Note that both of these shapes have reflective symmetry in the coordinate axes so it suffices to consider points P of tangential intersection in the first quadrant.
Anyone got an efficient method to solve 2001 Q8 b) i)
I feel that for 2 marks, should be under 1 page =.=
They should. Marking criteria for that Q is on Page 15 here: http://arc.boardofstudies.nsw.edu.a.../support_documentation/math_ext2_guide_01.pdfCheers pokemon hunter, If I wrote that in the HSC, will they accept it and give the 2 marks?
its not hard once you learn it -.- trust me if you are capable to extension 2Far this stuff looks hard, I'm sticking to 2 Unit.
The slicing method uses . So you need to find the area of a typical slice at a point x (this isA(x)), and integrate this area function over the given interval.I dont understand volumes slicing method D: i can't do even the simplest questions... need help
EDIT: for example i dont know what to put as the arbitary value of the x or y slice
a simple question:The slicing method uses . So you need to find the area of a typical slice at a point x (this isA(x)), and integrate this area function over the given interval.
The volume would be given by:a simple question:
solid explanationThe volume would be given by:
You substitute: and integrate accordingly
Since the radius of the cylinders are 4-x, and the height/thickness of the cylinders is dy, you use the formula pir^2h to find the volume. The integral is the summation of the cylinders between 0 to 4solid explanation
(It helps to draw a diagram)a simple question: