Speed’o’sound Sonic
Well-Known Member
- Joined
- Nov 4, 2019
- Messages
- 495
- Gender
- Male
- HSC
- 2020
NoiceEngi type stuff
But I'm indecisive, so that might change.
NoiceEngi type stuff
But I'm indecisive, so that might change.
When you take the log of something, the number of significant figures becomes the amount of decimal places of the answer. For example, -log(4.3E-3) ≈ 2.37.Hi lads and lasses,
when rounding up pH and pOH do u recommend rounding up to sig figs or decimal places? Because for the whole year my teacher has been telling us to round it up to one decimal places, but hsc Sample solutions suggest otherwise
that means -log (4.3*10^-3)I’m not sure I know what you mean. Can you explain what ‘-log(4.3E-3)‘ means?
-log (4.3*10^-3) = 2.367 = 2.36 to 3 sig figs. It it was pH, it would be to decimal places not sig figs i.e. 3 sig figs is 13.000 for pH not 13.0But how would that be 3 sig figs like what he said?
Not specifically I don't think (like we don't have to know specific biopolymer's structures), but it would be good to know just a few properties just in caseDo we need to know about biopolymers? Thanks!
Cool thanks mate. Hope the questions tomorrow don't get too complicated with NMR.I think it should.
View attachment 29461
The central hydrogen will see 5 neighboring hydrogens in unique environments. N + 1 rule will produce 6 peaks.
I always just draw them all and think about where the functional groups can move or possible different arrangements of the carbon chain.Does anybody have any tips on questions asking how many isomers of a compound there are. I always get them wrong haha
k thanks coz I always either get one higher or one lower than the answer haha, they're so time consumingI always just draw them all and think about where the functional groups can move or possible different arrangements of the carbon chain.
There might be a mistake in the question because they haven't told you the molar mass of the sample or the moles so it would be impossible to find the number of monomersView attachment 29468Hello, can someone please help with part 2.
yeah there's a missing step there coz they just go from moles to monomers without any in-between step. The writing is pretty bad also nglI figured something was missing... So the second last step to the last one, that's where you multiply by molar mass...?View attachment 29469
ok thanks for the clarification!yeah there's a missing step there coz they just go from moles to monomers without any in-between step. The writing is pretty bad also ngl
btw for those polymer questions where they ask you to calculate the molar mass of a condensation polymer, you have to subtract n-1 number of water molar masses, where n is number of monomers not n water's, because 2 monomers join to form 1 water, so there's 1 less water.ok thanks for the clarification!
im pretty sure when they got number of moles they multiplied that by avagadros constant (6.022*10^23). i have no idea why they used that constant thoI figured something was missing... So the second last step to the last one, that's where you multiply by molar mass...?View attachment 29469