Let I =^ cbf doing that lol
New Q:
For original question answer is:
if I am not mistaken
Edit
Mr Ivanovic
Last edited:
-
Finished your HSC? Check out our University Discussion, Non-School forums or help out next year's HSC students! -
YOU can help the next generation of students in the community! Share your trial papers and notes on our Notes & Resources page
HSC Mathematics Marathon (2 Viewers)
- Thread starter ohexploitable
- Start date
For original question answer is:
if I am not mistaken
Edit
Mr Ivanovic
Yep, I already see where I went wrong, namely leaving tan 2x out of there somewhere (which I'm assuming was important). Stuff this, I'm doing it on paper, scanning it and posting the image. Can't read my own typing...
C'mon. Don't be harsh on yourself. You are no different from the 95% who sux in spelling and grammar. These are unimportant. Trust me; they (sorry: ought to be these, haha) don't count anymore. Most of your younger English teachers are in the same boat.
Last edited:
It's more that usually I'm fine at it, but sleep deprivation has degraded me to a veritable husk of who I once was. I'm going to come out the other end of those exams and I'll be spelling properly and properly reading my coding once more (I hope)
More seriously ZachBC-94, I was just pulling your leg and having a dig at the state of English spelling/grammar in today's cyberworld. Only people from the dinosaur age worry about such things.
And this coming from an n.e.s.b.
And this coming from an n.e.s.b.
Last edited:
And it is for precisely that reason that I do care.
Because once everything is shortened, and people start accepting devine instead of divine as acceptable, we start to lose something. It's like Marshall McLuhan said, with every technological advancement, we effectively amputate some function of our body. Only now, we are amputating the English language.
Because once everything is shortened, and people start accepting devine instead of divine as acceptable, we start to lose something. It's like Marshall McLuhan said, with every technological advancement, we effectively amputate some function of our body. Only now, we are amputating the English language.
I can see you are a very sensible young man.
One of the casualties of the computer age is the collapse in the standard of handwriting. Understandably, apart from having to use it still for the HSC, it is not much used nowadays. 40 years ago some employers require job seekers to send in their applications in their own handwriting. I thought only handwriting in English has gotten crap. But I have read that the same malaise aflicts the Chinese as well.
Also on bos I have seen many people talk about how to write faster. They talk about pens & various attachments and aids. And secrets. They are like the proverbial blind leading the blind. My offer to teach handwriting has elicited relatively little interest.
One of the casualties of the computer age is the collapse in the standard of handwriting. Understandably, apart from having to use it still for the HSC, it is not much used nowadays. 40 years ago some employers require job seekers to send in their applications in their own handwriting. I thought only handwriting in English has gotten crap. But I have read that the same malaise aflicts the Chinese as well.
Also on bos I have seen many people talk about how to write faster. They talk about pens & various attachments and aids. And secrets. They are like the proverbial blind leading the blind. My offer to teach handwriting has elicited relatively little interest.
Last edited:
hscishard
Active Member
Drongoski is 1 of those wise ppl. You can so tell
It's a shame.
The worst thing though, is that it could be avoided. It is the unquestioning acceptance of the masses that gets me.
I guess that is what I admire most in the leading faces of the computer profession. It is those whose life is embodied by technology that seem to be able to see the importance of language.
I only hope we can diverge from the sad path we have set ourselves upon before translations of Hamlet look a lot more like - "2 B or nt 2 B, tht is ta qstn"
The worst thing though, is that it could be avoided. It is the unquestioning acceptance of the masses that gets me.
I guess that is what I admire most in the leading faces of the computer profession. It is those whose life is embodied by technology that seem to be able to see the importance of language.
I only hope we can diverge from the sad path we have set ourselves upon before translations of Hamlet look a lot more like - "2 B or nt 2 B, tht is ta qstn"
UnrealAnchovies
Member
- Joined
- Apr 3, 2010
- Messages
- 777
- Gender
- Male
- HSC
- 2011
orite, new qstn:
The equation x^n - px^(n-1) + q = 0 has a multiple root. Show that p^n (n-1)^(n-1) = qn^n
The equation x^n - px^(n-1) + q = 0 has a multiple root. Show that p^n (n-1)^(n-1) = qn^n
Can you LaTeX this so it is less ambiguous?
hscishard
Active Member
Not sure if there's a better way, I haven't done polynomials
i) is quite simple, -b/a and c/a
ii) You create a quadratic equation with roots a^10 and b^10
Let u=x^(1/5), solve via quadratic formula. You will get 2 complex roots. Add them(i.e. a^10 + b^10) and then use de-moivres theorem
i) is quite simple, -b/a and c/a
ii) You create a quadratic equation with roots a^10 and b^10
Let u=x^(1/5), solve via quadratic formula. You will get 2 complex roots. Add them(i.e. a^10 + b^10) and then use de-moivres theorem
hscishard
Active Member
Someone post next question
hscishard
Active Member
Oh man. There are too many ways of interpreting that. My guess is you differentiate it find a root and then sub it in.
EDIT:
dividing X and Y externally with ratio b^2 and a^2 to get P
^thats the question btw \text{lies on the ellipse}\: \frac{x^2}{a^2}+\frac{y^2}{b^2}=1.\\\\\text{The normal at P cuts the x-axis at X and the y-axis at Y.}\\\\\text{Show that}\frac{PX}{PY}=\frac{b^2}{a^2})
even easier method:
dividing X and Y externally with ratio b^2 and a^2 to get P
Last edited:
rawrence
Member
New question, polynomials:
 is divided by } (x^2+1) \text{ the remainder is } Ax+B\\\\\text{ i) Show that } A=\frac{P(i)-P(-i)}{2i} \text{ and }B=\frac{P(i)+P(-i)}{2}\\\\\text{ii) If P(x) is odd, find the remainder when P(x) is divided by }(x^2+1))