HSC Physics Marathon 2013-2015 Archive (1 Viewer)

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deswa1

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Re: 2013 HSC physics marathon

Q. Identify a reason postulated for the Null Result given by the MM experiment.
The MM experiment attempted to find the Earth's relative velocity through the use of the aether model however the results suggested that no motion of the Earth relative to the aether which led to scientists of the time to the conclusion that the aether was a flawed idea and it simply did not exist.
However, the MM experiment didn't actually disprove the existence of an aether model but rather it concluded that the earth's velocity relative to the aether was in-measurable.


not sure if im addressing the question here tbh, feel free to rip into my response ;)
I don't think you even answered the question. You need to give a reason as to why the null result occured.

That's a good effort Immortalp00n.

I was thinking more along the lines of this as a response:
A null result is produced when an experiment does not produce the expected result. Reasons postulated for the null result of the MM experiment are;
- Massive objects can drag the aether along with it, hence Earth being stationary relative to the aether (the aether was being dragged along by Earth).
- The length in direction of the aether was contracted.
I've never heard of those (they could still be right though). About the first, I thought one of the properties of the aether was that it was an absolute frame of reference, encompassed all space etc. -> the Earth can't 'drag' the aether along. For your second, why would you experience length contraction? This is a relativistic effect.

Personally, I would answer like this (remembering that this is just an identify question):

The aether does not exist
 

premskies

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Re: 2013 HSC physics marathon

For your second, why would you experience length contraction? This is a relativistic effect.
Yeah, scientists could later reason that length contraction wasn't responsible since it was a relativistic effect. However at the time, some people believed that length contraction had occurred in the arm parallel to the direction of motion of the apparatus. Again, its just a postulate so this wasn't thought or believed by many, though it was a valid reason in regards to their understanding of relativity at the time.
 

Immortalp00n

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Re: 2013 HSC physics marathon

so pretty much the MM experiment sought to measure the earth's velocity relative to the aether however the aether did not exist, yielding a null result???


new question:
Discuss the issues associated with safe re entry into the Earth's Atmosphere and the precautions and safety measures taken to overcome said issues.
 

premskies

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Re: 2013 HSC physics marathon

so pretty much the MM experiment sought to measure the earth's velocity relative to the aether however the aether did not exist, yielding a null result???
Yeah that's exactly right. Those postulates are just reasons that people suggested as to why the yield result occurred (not factual).

new question:
Discuss the issues associated with safe re entry into the Earth's Atmosphere and the precautions and safety measures taken to overcome said issues.
How much marks? This could potentially be a 3-4 or 7-8 marker?
 

Immortalp00n

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Re: 2013 HSC physics marathon

Yeah that's exactly right. Those postulates are just reasons that people suggested as to why the yield result occurred (not factual).



How much marks? This could potentially be a 3-4 or 7-8 marker?
okay sweet.

and i'd say a 6 marker
coz there are a few issues and many ways to overcome em..
 

premskies

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Re: 2013 HSC physics marathon

new question:
Discuss the issues associated with safe re entry into the Earth's Atmosphere and the precautions and safety measures taken to overcome said issues.
Issue: There is an optimum angle for safe re-entry for a manned spacecraft. Failure to meet such an angle can result in fatality and destruction. Other factors that need to be taken into consideration and appropriately treated in order for a safe re-entry are acceleration of the spacecraft, g-forces experienced by the spacecraft and lastly, the heat of the spacecraft.

Heat: The considerable amount of kinetic and potential energy possessed by an orbiting spacecraft must be lost during re-entry. As the atmosphere decelerates the spacecraft, the energy is converted into a large amount of heat, which must be tolerated and/or minimized. Spacecrafts with a 'blunt nose' produce a shockwave of air in front of them, which allows for a large amount of the frictional heat to be absorbed. Heat can also be tolerated through use of heat shields that use ablating tiles. The ablation layer vaporises or ablates under extreme heats and therefore, dissipates heat during re-entry. Porous Silica tiles are an alternative that can be placed on the exterior of the spacecraft. They dissipate (instead of ablating) large amounts of heat and are extremely good insulators. They are beneficial is that they don't require any excess of fuel in order to be carried, since they are relatively very light (composed of 90% air). Lastly, heat can be minimized by taking a longer period of time to re-enter, thereby lengthening the time over which energy is converted into heat. This essentially allows for an avoidance of any substantial accumulation of heat that can damage the spacecraft and the occupants within it.


Ionisation Blackout: Radio blackouts occur during a period of re-entry. They are caused by overheated air particles ionizing as they collide with the spacecraft. Radio signals are unable to penetrate these air particles and therefore, raises concern if contact is required between the spacecraft and Earth. The issue can only really be avoided or minimized, through planning the mission more carefully such that when they go into that period, the astronauts are self-sufficient and therefore, don't require communication through radio contact.

Decelerating G-Forces: The deceleration of a re-entering spacecraft produces g-forces, which are typically greater than those experienced at launch (~20g). High g-forces can potentially kill occupants and certain procedures are vital for safe re-entry. Such high g-forces are able to be tolerated by reclining the astronaut, such that blood in the body is not forced away from the brain (it also fully supports the body). Such reclining of the body is achieved through the use of a moulded fibreglass couch. G-forces can further be minimised by extending the re-entry, slowing the rate of descent.
 

RivalryofTroll

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Re: 2013 HSC physics marathon

Here's a somewhat tricky question for you guys to answer.

HSC 2006 question. (3 marks)

An object is stationary in space and located at a distance 10000km from the centre of a certain planet. It is found that 1.0MJ of work needs to be done to move the object to a stationary point 20000km from the centre of the planet.
Calculate how much more work needs to be done to move the object to a stationary point 80000km from the centre of the planet.
 

Immortalp00n

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Re: 2013 HSC physics marathon

Here's a somewhat tricky question for you guys to answer.

HSC 2006 question. (3 marks)

An object is stationary in space and located at a distance 10000km from the centre of a certain planet. It is found that 1.0MJ of work needs to be done to move the object to a stationary point 20000km from the centre of the planet.
Calculate how much more work needs to be done to move the object to a stationary point 80000km from the centre of the planet.
work done is the change in potential energy right
ep=-g x m1m2/r
from 10000 to 20000 it took 1.0MJ ( 1x10^6 J)
1x10^6=- G X M1M2/20000 X 10^3 - (-G x m1m2/10000 x 10^3)
20000x 10^3 x1x10^6=-Gm1m2 + 2Gm1m2
Gm1m2=2 x 10^13

to move from 20000--> 80 000km
-G x m1m2/80000 x 10^3 + G x m1m2/r
= - 2x 10^13/80000 x 10^3 + 2x10^13/20000x 10^3
Change in potential energy= -250000 + 1000 000 = 750000
divide by 10^6
work done= 0.75 MJ
 
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Immortalp00n

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Re: 2013 HSC physics marathon

fuark wish i knew how to latex:(
 

RivalryofTroll

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Re: 2013 HSC physics marathon

work done is the negative change in potential energy right
ep=-g x m1m2/r
from 10000 to 20000 it took 1.0MJ ( 1x10^6 J)
1x10^6=- G X M1M2/20000 X 10^3 - (-G x m1m2/10000 x 10^3)
20000x 10^3 x1x10^6=-Gm1m2 + 2Gm1m2
Gm1m2=2 x 10^13

to move from 20000--> 80 000km
-G x m1m2/80000 x 10^3 + G x m1m2/r
= - 2x 10^13/80000 x 10^3 + 2x10^13/20000x 10^3
Change in potential energy= -250000 + 1000 000 = 750000
divide by 10^6
work done= 0.75 MJ
3/3.

Excellent work champ.
 

nightweaver066

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Re: 2013 HSC physics marathon

Issue: There is an optimum angle for safe re-entry for a manned spacecraft. Failure to meet such an angle can result in fatality and destruction.What happens if its coming in too shallow/steep? Other factors that need to be taken into consideration and appropriately treated in order for a safe re-entry are acceleration of the spacecraft, g-forces experienced by the spacecraft and lastly, the heat of the spacecraft.

Heat: The considerable amount of kinetic and potential energy possessed by an orbiting spacecraft must be lost during re-entry. As the atmosphere decelerates the spacecraft, the energy is converted into a large amount of heat, which must be tolerated and/or minimized. Spacecrafts with a 'blunt nose' produce a shockwave of air in front of them, which allows for a large amount of the frictional heat to be absorbed. Heat can also be tolerated through use of heat shields that use ablating tiles. The ablation layer vaporises or ablates under extreme heats and therefore, dissipates heat during re-entry. Porous Silica tiles are an alternative that can be placed on the exterior of the spacecraft. They dissipate (instead of ablating) large amounts of heat and are extremely good insulators. They are beneficial is that they don't require any excess of fuel in order to be carried, since they are relatively very light (composed of 90% air). Lastly, heat can be minimized by taking a longer period of time to re-enter How do you do this?, thereby lengthening the time over which energy is converted into heat. This essentially allows for an avoidance of any substantial accumulation of heat that can damage the spacecraft and the occupants within it.


Ionisation Blackout: Radio blackouts occur during a period of re-entry. They are caused by overheated air particles ionizing as they collide with the spacecraft. Radio signals are unable to penetrate these air particles and therefore, raises concern if contact is required between the spacecraft and Earth. The issue can only really be avoided or minimized, through planning the mission more carefully such that when they go into that period, the astronauts are self-sufficient and therefore, don't require communication through radio contact.

Decelerating G-Forces: The deceleration of a re-entering spacecraft produces g-forces, which are typically greater than those experienced at launch (~20g). High g-forces can potentially kill occupants and certain procedures are vital for safe re-entry. Such high g-forces are able to be tolerated by reclining the astronaut, such that blood in the body is not forced away from the brain (it also fully supports the body). Such reclining of the body is achieved through the use of a moulded fibreglass couch. G-forces can further be minimised by extending the re-entry, slowing the rate of descent.
What about landing?

Pretty good answer overall :)
 

Immortalp00n

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Re: 2013 HSC physics marathon

What about landing?

Pretty good answer overall :)
The spacecraft must touch down softly onto the surface of the earth.
- use of russian capsules ( parachutes to slow the capsule down until astronauts could eject and fall using a parachute down to earth.
- Early American craft ( slowed down with parachutes and resulted in a soft landing on the ocean).
Since the space shuttle is unpowered, it has one chance at landing on the landing strip, so many measures must be taken to ensure that it is successful.
-The shuttle must be accurately guided, against drag and lift forces causing spacecraft to deviate from the original path of motion.
- The Spacecraft is designed with " lift" like an aeroplane so it can be manouvered and controlled during descent and landing.
 

iBibah

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Re: 2013 HSC physics marathon

Here's a somewhat tricky question for you guys to answer.

HSC 2006 question. (3 marks)

An object is stationary in space and located at a distance 10000km from the centre of a certain planet. It is found that 1.0MJ of work needs to be done to move the object to a stationary point 20000km from the centre of the planet.
Calculate how much more work needs to be done to move the object to a stationary point 80000km from the centre of the planet.


EDIT: Too slow D: Not latexing next time....
 

premskies

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Re: 2013 HSC physics marathon

What about landing?

Pretty good answer overall :)
Yeah I wasn't sure whether to mention landing, based on the wording of the question. I also probably went too in depth in some areas and not enough in others.

If the spacecraft re-enters at an angle too shallow (typically greater than 10degrees), the spacecraft may "skip" off the atmosphere and go back deep into space as a result of the compression of the atmosphere (high pressured) atmosphere below it.

With the time taken to re-enter, the most efficient way to lengthen the time of re-entry is to maximise the angle of re-entry, such that it takes a longer amount of time to re-enter (so less heat is produced as a result of friction, because the spacecraft is travelling slower, or decelerating at a greater rate), however is still at a great enough angle to not "skip off the atmosphere."

Thanks nightweaver066. :)
 
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premskies

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Re: 2013 HSC physics marathon

Q. Explain how the slingshot effect works.
 

Immortalp00n

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Re: 2013 HSC physics marathon

Q. Explain how the slingshot effect works.
The slingshot effect, defined as the increase in velocity given to a spacecraft because it enters the gravitational field of a planet as it passes by, is a technque used by Space agencies in accordance with physicists in order to take full advantage of a planets rotational motion in order to increase a particle's ( spacecraft) final speed.
The slingshot effect is used by many spacecraft which travel within and beyond the solar system.
A spacecraft passes close to a a planet such that its gravity pulls the spacecraft into an arc or circular motion.It leaves with the same speed relative to the planet, but its speed is increased when viewed from an alternate frame of reference such as the Sun.
The acquired speed is large enough so that the spacecraft can travel away from the planet.
Comparatively, a ball thrown from a person who is stationary would have speeds less than a ball thrown from a person who is running at an increasing or stationary speed. Thus the slingshot effect, also known as gravity assist trajectory is used in order to attain a significant change in speed and direction despite the very little expenditure of fuel, improving flight efficiency.
 
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