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I forgot the clever way of doing these integrals... (1 Viewer)

Drongoski

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If numerator were: sin2x + 4sinxcosx + 3cos2x things would be much easier.

In this case numerator = (sinx + 3cosx)(sinx + cosx). But as it stands, I have not figured out how. Alternatively, were the denominator (sinx - cos x) it'd also be simple.

The numerator as it stands = (sinx - cosx)(sinx - 3cosx)
 
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