I impulsory New Member Joined Mar 9, 2009 Messages 8 Gender Male HSC 2010 Mar 9, 2009 #1 a^3(b^2)^3 -------------- a^4 b^4 where a = 2/3 and b = 8/9 so confused hahaif its ok can someone please help me? test tomorrow
a^3(b^2)^3 -------------- a^4 b^4 where a = 2/3 and b = 8/9 so confused hahaif its ok can someone please help me? test tomorrow
WannaBang? Member Joined May 6, 2008 Messages 349 Gender Male HSC 2008 Mar 9, 2009 #2 i think it's a maths equation of some sort.
I impulsory New Member Joined Mar 9, 2009 Messages 8 Gender Male HSC 2010 Mar 9, 2009 #3 Mad props for the awesome tips.
WannaBang? Member Joined May 6, 2008 Messages 349 Gender Male HSC 2008 Mar 9, 2009 #4 impulsory said: Mad props for the awesome tips. Click to expand... i do my best.
I impulsory New Member Joined Mar 9, 2009 Messages 8 Gender Male HSC 2010 Mar 9, 2009 #5 Evidently. Someone please, you lot are intelligent.
D Drongoski Well-Known Member Joined Feb 22, 2009 Messages 4,255 Gender Male HSC N/A Mar 9, 2009 #6 impulsory said: Evidently. Someone please, you lot are intelligent. Click to expand... [a^3 (b^2)^3] / [a^4 b^4] = [a^3 b^6] / [a^4 b^4] = b^2/a = (2/3)^2 / (8/9) = (4/9) x (9/8) = 1/2 Oh dear - I substituted the wrong values: = (8/9)^2 / (2/3) = 32/27 per lolokay Last edited: Mar 9, 2009
impulsory said: Evidently. Someone please, you lot are intelligent. Click to expand... [a^3 (b^2)^3] / [a^4 b^4] = [a^3 b^6] / [a^4 b^4] = b^2/a = (2/3)^2 / (8/9) = (4/9) x (9/8) = 1/2 Oh dear - I substituted the wrong values: = (8/9)^2 / (2/3) = 32/27 per lolokay
L lolokay Active Member Joined Mar 21, 2008 Messages 1,015 Gender Undisclosed HSC 2009 Mar 9, 2009 #7 "where a = 2/3 and b = 8/9" so (64/81)/(2/3) = 32/27
I impulsory New Member Joined Mar 9, 2009 Messages 8 Gender Male HSC 2010 Mar 9, 2009 #8 thanks heaps.