Inequalties Question (1 Viewer)

wrxsti

Rambo
Joined
Jul 20, 2006
Messages
1,653
Location
Nandos
Gender
Male
HSC
2007
1/(x-1)(x-3) < -1 any help wud be appreciated :S....
 

malady

New Member
Joined
Jun 10, 2006
Messages
13
Gender
Male
HSC
N/A
1/((x-1)(x-3))+1<0
so (x-2)^2/((x-1)(x-3))<0
only soln for this is 1<x<3
 

malady

New Member
Joined
Jun 10, 2006
Messages
13
Gender
Male
HSC
N/A
the answer is missing an x between the 1 and 3 .... for some reason its not printing right
<x>
<x></x></x>
 

Bank$

Member
Joined
Mar 13, 2006
Messages
150
Location
Parramatta
Gender
Male
HSC
2007
Here is my solution, having not done inequalities for sometime i used a purely algebraic approach which can become messy and result in stupid mistakes so if u do find any please post.


EDIT: srry the last part is wrong x cannot be zero so the answer is x greater than 1 and smaller than 2 or x greater than 2 and smaller than 3

Justin
 
Last edited:

Yip

Member
Joined
Sep 14, 2005
Messages
140
Gender
Male
HSC
2006
Since no one has pointed it out yet user Bank$, your approach, though mathematically correct, is also inefficient. It is not required to expand the expressions then factorize the cubic. It is much more efficient to go like this:

(x-1)(x-3)+[(x-1)(x-3)]^2<0
(x-1)(x-3)[1+(x-1)(x-3)]<0
(x-1)(x-3)(x^2-4x+4)<0
(x-1)(x-3)(x-2)^2<0
1< x <2, 2< x <3
Note that x cannot equal 2 as the inequality is <, not <=.
 
Last edited:

kony

Member
Joined
Feb 10, 2006
Messages
322
Gender
Undisclosed
HSC
2007
draw the graph of f[x] = 1/(x-1)(x-3)

there's a double root at x=2. and asymptotes at x = 1 and x = 3.

therefore, 1<x<3, excluding 2
 

~shinigami~

~Summer Song~
Joined
Nov 7, 2005
Messages
895
Location
Adelaide
Gender
Male
HSC
2007
Yip said:
Since no one has pointed it out yet user Bank$, your approach, though mathematically correct, is also inefficient. Your answer is also partly incorrect. It is not required to expand the expressions then factorize the cubic. It is much more efficient to go like this:

(x-1)(x-3)+[(x-1)(x-3)]^2<0
(x-1)(x-3)[1+(x-1)(x-3)]<0
(x-1)(x-3)(x^2-4x+4)<0
(x-1)(x-3)(x-2)^2<0
1<x<2, 2<x<3
Note that x cannot equal 2 as the inequality is <, not <=.
I need help with a maths question...can you explain your avatar? =p

Love is the primitive of ???
 

Yip

Member
Joined
Sep 14, 2005
Messages
140
Gender
Male
HSC
2006
Passion, which is a function of time
 

Bank$

Member
Joined
Mar 13, 2006
Messages
150
Location
Parramatta
Gender
Male
HSC
2007
Yip said:
Your answer is also partly incorrect.
Where ? If u are talking about x not equal to 2 i added that in right after my post under edit.

Yip said:
(x-1)(x-3)+[(x-1)(x-3)]^2<0
(x-1)(x-3)[1+(x-1)(x-3)]<0
(x-1)(x-3)(x^2-4x+4)<0
(x-1)(x-3)(x-2)^2<0
1< x <2, 2< x <3
I do agree with the inefficientcy of my methord i guess ill have to go back a revise on yr 11 lol.
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top