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Integral of a quarter-circle (1 Viewer)

Heresy

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Find the area bounded by the curve y = (4-x^2)^1/2, the x-axis and the y-axis in the first quadrant.

I know what the integral is, but whenever I try to solve it I end up with 16/3 - when the answer should be pi units^2

Any help would be appreciated. Thanks.
 
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fan96

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something that should be explicitly noted is that



(and in general, )

usually the bounds of the integral will mean that but one should still be careful when dealing with situations like this.
 

Heresy

Member
Joined
Nov 13, 2017
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2019
something that should be explicitly noted is that



(and in general, )

usually the bounds of the integral will mean that but one should still be careful when dealing with situations like this.
Thank you.

On a completely unrelated note - how do you type in that font with the equations - I'm curious lol - it will make it 10 times easier next time I inevitably ask for help ;)
 

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