integration area of sinx and cos x (1 Viewer)

[cloud edwards]

So, How does one find the total shaded area (red and green in the attachment).
I'm unsure whether the first half (red part) is going to be the integral of sinx or (cosx -sinx)

My instinct working out for total area of the shaded:

integration of sin x between 0 and 45 + [integration of sinx -cos x in between 45 to 90]

 

[1729]

So, How does one find the total shaded area (red and green in the attachment).
I'm unsure whether the first half (red part) is going to be the integral of sinx or (cosx -sinx)

My instinct working out for total area of the shaded:

integration of sin x between 0 and 45 + [integration of sinx -cos x in between 45 to 90]

 

[cloud edwards]

Ok thanx, so how did u get the second half (i.e. cosx)

 

[1729]

Ok thanx, so how did u get the second half (i.e. cosx)

 

[cloud edwards]

Thanx bro, you're a lifesaver!

 

[integral95]

Going to be a bit pedantic here, but you shouldn't be using your limits in terms of degree but in radians, it could create a lot of awkward scaling factors especially if you're combining trig functions with some linear function.

e.g

wouldn't give you the right value for the area under the curve.

 

[cloud edwards]

How different would it be if i didn't use radians, i'm a bit confused with the example,
sorry.

 

[dan964]

How different would it be if i didn't use radians, i'm a bit confused with the example,
sorry.

It is how the derivative of cos x and sin x is defined. We use radians instead of degrees as the computation is simpler.
for x in degrees

 

[cloud edwards]

Ok sweet, thanx guys