integration from trial (1 Viewer)

[bboyelement]

just did my trial today theres one integration question i couldnt get ... its a 3 mark as well ... so disappointed but anyways

S 2/(4+3sin[theta]) d[theta] using substitution t=tan[theta/2]

 

[bboyelement]

Hmm, I couldn't get it either... After substitution I got it down to
Int[2 / (2t^2+3t+2)]dt but I couldn't split that so perhaps I made an error somewhere or forgot something. *sigh* it is depressing not having done Maths for atleast a week because of fear of failing English.

lol... same i remembered sitting there asking myself did i lose all my maths skills because of studying too much for english or what ... but i think i have to check it with my teacher because this question is not possible to integrate at the 4 unit maths level

 

[Raginsheep]

umm......complete the square?

Final answer is (4/√7)arctan(4(t+3/4)/√7)+c and just sub in for t

 

[bboyelement]

umm......complete the square?

Final answer is (4/√7)arctan(4(t+3/4)/√7)+c and just sub in for t

hahha shamed ... thanks