Z zeek Member Joined Sep 29, 2005 Messages 549 Location ummmmm Gender Male HSC 2006 Jun 12, 2006 #1 Hey guys, can anyone do this question please... Integral of [x/(1-x^2)^(3/2) dx] sorry about the formatting thx
Hey guys, can anyone do this question please... Integral of [x/(1-x^2)^(3/2) dx] sorry about the formatting thx
R Riviet . Joined Oct 11, 2005 Messages 5,593 Gender Undisclosed HSC N/A Jun 12, 2006 #2 Let u=1-x2 du=-2x dx x dx = -du/2 Substitute into integral and you should be able to do the rest.
Z zeek Member Joined Sep 29, 2005 Messages 549 Location ummmmm Gender Male HSC 2006 Jun 12, 2006 #3 oops i forgot to mention that i needed to solve it using trig substitution thx
Z zeek Member Joined Sep 29, 2005 Messages 549 Location ummmmm Gender Male HSC 2006 Jun 12, 2006 #4 dw i got it now lol thanks for the help though riviet
Z zeek Member Joined Sep 29, 2005 Messages 549 Location ummmmm Gender Male HSC 2006 Jun 12, 2006 #5 ok what about this one integral of [(x^2 + 3)/(x^2 + 9)^(1/2)] dx using trig substitution please thx Answer is x/2.sqrt(x^2 + 9) - 3/2.ln(sqrt(x^2 + 9) + x) + K .... dw i've got that too now Last edited: Jun 12, 2006
ok what about this one integral of [(x^2 + 3)/(x^2 + 9)^(1/2)] dx using trig substitution please thx Answer is x/2.sqrt(x^2 + 9) - 3/2.ln(sqrt(x^2 + 9) + x) + K .... dw i've got that too now