Integration question (1 Viewer)

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If you have the Terry Lee, it's question 1(p) in Review Exercise 4.9.

But for those who don't, this is the question:

Integrate: sq.root (1 + 4x) / (1-4x) dx (the whole fraction is under a sq.root).

It's probably something really straightforward that I can't see...

Thanks in advance.
 

Shadowdude

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Is it... this?



If so, I'll get my notepad out and start figuring it out.
 
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Yeah it is Shadowdude.

And I'll give that a go, thanks iSplicer.

Edit: It came out with iSplicers advice. Thanks!
 
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Drongoski

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Is it... this?



If so, I'll get my notepad out and start figuring it out.

integral = int sqrt[(1+4x)(1+4x)/(1-4x)(1+4x)] dx = int (1+4x)/sqrt(1-(4x)^2) dx

= int 1/sqrt(1 - (4x)^2) dx + int (1 - 16x^2)^(-0.5)4x dx

= 1/4 sin^-1 (4x) - 1/8 int (1 - 16x^2)^(-0.5)d(1-16x^2)

= 1/4 sin^-1(4x) - 1/4 sqrt (1- 16x^2) + C







Edit: I have been struggling to get my TeX version right ! Ha Ha!
 
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