Integration question (1 Viewer)

qUiCkMaThS

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well, idk what I've done wrong, but if you find it, just point it out:

A1 + A2 + A3 = ATotal
A2 + A3 = 5A1/ 2

Since A1 = 3 x 2 = 6

ATotal = 15+6 = 21

i got 21 aswell, but I thought we subtract the bottom two from the area of the top? not sure tho
I've forgotten whether 'evaluate' changes what the question is asking....sorry about that!
 
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well, idk what I've done wrong, but if you find it, just point it out:

A1 + A2 + A3 = ATotal
A2 + A3 = 5A1/ 2

Since A1 = 3 x 2 = 6

ATotal = 15+6 = 21



I've forgotten whether 'evaluate' changes what the question is asking....sorry about that!
no problem!! that's exactly what I got, it may be an error in the question, thank you!!
 

B1andB2

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A1=6
A2= 3
A3 = 5(3x2)-2(3)/2 = 12

when you evaluate the integral (not the same as finding area) you consider the fact that below= negative

so solving the integral = -6+3-12 = -15
 
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A1=6
A2= 3
A3 = 5(3x2)-2(3)/2 = 12

when you evaluate the integral (not the same as finding area) you consider the fact that below= negative

so solving the integral = -6+3-12 =15
yesss that makes sense, thank you tooo!!
 

YonOra

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A1=6
A2= 3
A3 = 5(3x2)-2(3)/2 = 12

when you evaluate the integral (not the same as finding area) you consider the fact that below= negative

so solving the integral = -6+3-12 = -15
How'd u get A2 to be 3. Having an elderly moment
 

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