interesting brain teaser:P (1 Viewer)

zeebobDD

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Find the ph of HCL 1x10^-8 mol/L, the answer is not 8. lol apparently it is 6.9 sumthin can anyone tell me how?
 

Carrotsticks

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This is not really a brain teaser.

Generally, brain teasers can be done by anybody with no extra knowledge apart from common sense and basic logic.
 

someth1ng

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I think you need add the concentration of water (1x10^-7) and the concentration of HCl (1x10^-8) to determine the net pH then use the pH formula to determine the actual pH.
 

zeebobDD

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This is not really a brain teaser.

Generally, brain teasers can be done by anybody with no extra knowledge apart from common sense and basic logic.
well i did post it in the chemistry section, and you dont really have to be so technical about everything? who gives a shit what the title fkn says?
 

rolpsy

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for very weak concentrations (~10-6 M) the baseline concentration of H3O+ ions in pure water becomes significant, and must be taken into account
use this formula,

[H3O+] = Ca + Kw/[H3O+]

where Ca is the concentration of the acid, and Kw is the dissociation constant of water

substituting, we get [H3O+] = 1.05125×10-7 mol/L
and so pH = 6.97829

see chapter 3.

:p
 

someth1ng

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for very weak concentrations (~10-6 M) the baseline concentration of H3O+ ions in pure water becomes significant, and must be taken into account
use this formula,

[H3O+] = Ca + Kw/[H3O+]

where Ca is the concentration of the acid, and Kw is the dissociation constant of water

substituting, we get [H3O+] = 1.05125×10-7 mol/L
and so pH = 6.97829

see chapter 3.

:p
Can't you just do it:
[H+] in water=1x10^-7
[H+] provided by HCl=1x10^-8

Total [H+]=1.1x10^-7=6.96 or something like that?
 

rolpsy

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Can't you just do it:
[H+] in water=1x10^-7
[H+] provided by HCl=1x10^-8

Total [H+]=1.1x10^-7=6.96 or something like that?
except some of the H+ ions provided by the HCl will react with OH- ions to form water...
 

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