Inverse function question. Problem with point of intersection. (1 Viewer)

[DuhBoyChong]

Hello, im having trouble with sketching the inverse function of f(x)= tan(x/2), -π≤x≤π .

I have the domain, range, period, and phase. I have drawn the mirror y=x, but i can't find the point of intersection. in which i equate y=x, and y=tan(x/2) to find where the mirror line and the forward function intersects. How do you simultaneously solve y=x, and y=tan(x/2),

It it x=tan(x/2)? Dunno what to do.

 

[integral95]

Are you just required to sketch the inverse function, in that case you just need the equation of the inverse equation and not worry about the point of intersection with y = x

 

[DuhBoyChong]

Are you just required to sketch the inverse function, in that case you just need the equation of the inverse equation and not worry about the point of intersection with y = x

Yea, sorry, the domain was -π≤x≤π and thanks.

 

[InteGrand]

By the way, those should be strict inequalities for the (natural) domain (), since the tan function would be undefined at the boundaries.