ashokkumar
Mr
Let y = x^3 - 3x^2 - 1 (for x >=2). Find the slope of the tangent to the inverse function at x = -1.
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Let f(x) = x³ - 3x² - 1Let y = x^3 - 3x^2 - 1 (for x >=2). Find the slope of the tangent to the inverse function at x = -1.
I'm not sure about the logic behind that...I think the way you got the same answer might be a coincidence...is there a simpler way of doing this?
I simply differentiated the the original equation, found the reciprocal (i.e. dx/dy) and then subbed in x = -1 and i got the same answer (1/9).
Or is that method incorrect?