Inverse Trig. (1 Viewer)

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The inverse sine function can only operate on numbers in the domain of .

For the given function , the only restriction is that , which you must solve to find that the domain is actually or, in interval notation, .

Had the question asked for the domain of , you would have needed to solve to get a domain of .

Finally, had the question asked for the domain of , you would still have needed to solve but subject to the additional constraint that , producing a domain of .
 

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