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Inverse (1 Viewer)

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Thanks. How do you know by inspection the domain without solving inequality?
note the domain of inverse sine is -1 <= x <= 1

if you graph the numerator and the denominator separately you will find that one is always greater than the other and hence the quotient is less than one for all real x.

simplifying the LHS inequality gives you x^2 >= 0 which is also true for all real x.
 

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