isosceles triangles (1 Viewer)

lucymowat

New Member
Joined
May 22, 2008
Messages
21
Gender
Female
HSC
2009
noooooo my dad figured it out
you just had to divide it into 2 right-angled triangles :(
 

BECBEC1992

New Member
Joined
Jan 31, 2009
Messages
5
Gender
Female
HSC
2009
Dammit it took me foreva on that question and I couldnt do it
 

bmn

Member
Joined
Sep 1, 2007
Messages
214
Gender
Male
HSC
2009
I done that, but I didn't label them as right angles... Wonder if I'll get the mark...
 

meilz92

where are my hair
Joined
Jul 22, 2008
Messages
3,399
Gender
Undisclosed
HSC
2009
Uni Grad
2014
wtf? i thought we had to divide it into 4 isoceles triangles?

im so conufsed. that was the most pathetic excuse for a HSC question ever.
 

imoO

Member
Joined
Apr 6, 2008
Messages
302
Gender
Male
HSC
2009
I walked out astounded that I couldn't draw some triangles
 

lucymowat

New Member
Joined
May 22, 2008
Messages
21
Gender
Female
HSC
2009
wtf? i thought we had to divide it into 4 isoceles triangles?
first u had to divide it into right angled ones and then into 2 isosceles in each ... that was how it related to the first question.... dammit wish i'd thought of it
 

rant

&&&&&&&&
Joined
Nov 22, 2007
Messages
200
Location
Sydney
Gender
Male
HSC
2009
this is what i did


not exactly mathematical but neither was the question
 

lolliepop2

New Member
Joined
Nov 15, 2008
Messages
14
Gender
Female
HSC
2009
That's what i did too. Do you think we will get marks for it though?
 

johony

Active Member
Joined
Dec 29, 2006
Messages
1,521
Gender
Male
HSC
2009
a ridiculously easy mark in hindsight, but at the time i probably overcomplicated the answer and i've probably lost a mark.
 

mitchwong650

Member
Joined
Apr 13, 2009
Messages
52
Gender
Undisclosed
HSC
2009
I can't believe so many people couldn't do this question!

what do you think c) i) to c) iv) were for?

simply construct a line from the top corner to the hypotenuse, and you've got two of the triangles like the one right above it, then construct line bisectors in both and voila.

Here:

 

Aquawhite

Retiring
Joined
Jul 14, 2008
Messages
4,946
Location
Gold Coast
Gender
Male
HSC
2010
Uni Grad
2013
The post above is correct and is what the examiners will be looking for... I don't know if they'll award the others that have 4 isosceles triangles... but they would be looking for this.

Shame I didn't do it XD
 

Finx

Member
Joined
Mar 29, 2008
Messages
375
Gender
Male
HSC
2009
I can't believe so many people couldn't do this question!

what do you think c) i) to c) iv) were for?

simply construct a line from the top corner to the hypotenuse, and you've got two of the triangles like the one right above it, then construct line bisectors in both and voila.

Here:

Would we still have received the mark if we didn't put the right angles in?
 

timmy_tummy

New Member
Joined
Mar 15, 2009
Messages
4
Gender
Undisclosed
HSC
2009
I can't believe so many people couldn't do this question!

what do you think c) i) to c) iv) were for?

simply construct a line from the top corner to the hypotenuse, and you've got two of the triangles like the one right above it, then construct line bisectors in both and voila.

Here:

YES THAT'S WHAT I DID! =)
they obviously wanted you to use the bits from above...
 

HTB

New Member
Joined
May 14, 2007
Messages
6
Gender
Undisclosed
HSC
N/A
errr....u only need the right angles when u divide it the first time down the middle

the other line goes across the middle, dividing the two sides into equal parts (lines intersecting parallel lines in the same ratio)

then its the same idea as the previous part, the other triangles arent necessarily right angled
 

mitchwong650

Member
Joined
Apr 13, 2009
Messages
52
Gender
Undisclosed
HSC
2009
errr....u only need the right angles when u divide it the first time down the middle

the other line goes across the middle, dividing the two sides into equal parts (lines intersecting parallel lines in the same ratio)

then its the same idea as the previous part, the other triangles arent necessarily right angled
This makes sense, as long as you make it clear that "E" and "F" are the midpoints you should be fine,

you must have a right angle for "AC" though, in order to make it relate to parts c) i) to c) iv)

so i suppose you don't HAVE to have right angles in the smaller triangles
 

cpt. fantastic

New Member
Joined
Apr 20, 2008
Messages
4
Location
Sydney
Gender
Female
HSC
2009
I can't believe so many people couldn't do this question!

what do you think c) i) to c) iv) were for?

simply construct a line from the top corner to the hypotenuse, and you've got two of the triangles like the one right above it, then construct line bisectors in both and voila.

Here:

thats not 4 isosceles triangles thats 4 isosceles trianges and 2 right angle triangles
 

lyounamu

Reborn
Joined
Oct 28, 2007
Messages
9,998
Gender
Male
HSC
N/A
That question has to be the most ridiculous question ever.

Thank God I didn't do 2 unit this year haha
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top