Drsoccerball
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Why you cut?When both paradoxicas are smarter then you
Why you cut?When both paradoxicas are smarter then you
damn shots fired ahahaWhen both paradoxicas are smarter then you
Slight correction, at C that's where the inequality is introduced.
Choose , then we have .
Now
as required.
A: double angle
B: s^2 + c^2 = 1
C: cosine attains max at 1
D: hypothesis
oh crap... I made an error!
double angle formula bruh
How do we justify dropping the -1?
Rinse and repeat
What do you mean?Slight correction, at C that's where the inequality is introduced.
That's not right. The two should be on top if you were using double angle.Let's start here
Apply triangle-inequality to get
where delta is something...
Paradoxica, use your magnificent algebraic manipulation skills
G-d damn I keep forgetting that the triangle inequality is now an ASSUMED result at uni.Let's start here
Apply triangle-inequality to get
where delta is something...
Paradoxica, use your magnificent algebraic manipulation skills
Since LHS in the expression is >1 subtracting by one reduces the value of the expression.How do we justify dropping the -1?
Thanks for reminding the second time. I thought I remembered my double angles...That's not right. The two should be on top if you were using double angle.
And if you did the algebraic conversion, then it should be
It is only one or the other. Not both.
Thanks. Yep, it wouldn't do much harm because we will then use triangle-inequality!G-d damn I keep forgetting that the triangle inequality is now an ASSUMED result at uni.
But wait you still didn't address the problem with statement A
http://www.wolframalpha.com/input/?i=1-cos(x)=2sin^2(x/2)
Though my instinct tells me that it will be negligible
Not negligible. It affects the final result.G-d damn I keep forgetting that the triangle inequality is now an ASSUMED result at uni.
But wait you still didn't address the problem with statement A
http://www.wolframalpha.com/input/?i=1-cos(x)=2sin^2(x/2)
Though my instinct tells me that it will be negligible
Pardon me, didn't mean negligible. Meant doesn't affect the method, just the answer.Not negligible. It affects the final result.
That doesn't look correct. The corollary of the triangle inequality does not state |a-b| < |a|-|b|
What if I replaced that - with a + keeping in mind |-1|=1That doesn't look correct. The corollary of the triangle inequality does not state |a-b| < |a|-|b|
the closest I know of is ||x|-|y||<|x-y|
But that contradicts what you suppose.