mlinger
New Member
Did anyone get an answer around 0.3m???
yeh i didmlinger said:Did anyone get an answer around 0.3m???
I did the exact same thing there, but still confuse which frame of reference is supposed to be shorter because I looked at the wording of the question, and it is the exact same phrase as part (b), mass dilation one; I thought my answer for mass is increasing so length should be decreasing judging by the formulae used.----Josh-E---- said:the original length was 0.24 metres. I got 0.19 metres for observers. Did you ppl who got 30 remember to times the square root of 0.64 rather than divide like time dilation
the lenght contracts, but if you are in the frame of reference there is nothing you can see to tell you whether u are stationary or moving with constant veloity, moving at .6C and therefore in the frame of reference of travel the length appears normal or .24m, an external observer however can see that the length has contracted .3m is wrongSober said:You do not need to hope, it was definantly 0.3. An accellerated particle will see objects around them thinner than they really are, hence 0.24 is less than the real length. Most people I spoke to in my class got it wrong.
the thing you are measuring is in YOUR reference frame, NOT THE ELECTRONS.yorky said:the lenght contracts, but if you are in the frame of reference there is nothing you can see to tell you whether u are stationary or moving with constant veloity, moving at .6C and therefore in the frame of reference of travel the length appears normal or .24m, an external observer however can see that the length has contracted .3m is wrong