L Lukybear Active Member Joined May 6, 2008 Messages 1,466 Gender Male HSC 2010 Nov 6, 2009 #1 The latus rectum of a parabola has endpoints (-2,3) and (6,3). Find two possible equations for the parabola. Very difficult for me.
The latus rectum of a parabola has endpoints (-2,3) and (6,3). Find two possible equations for the parabola. Very difficult for me.
gurmies Drover Joined Mar 20, 2008 Messages 1,207 Location North Bondi Gender Male HSC 2009 Nov 6, 2009 #2 End points are (-2,3) and (6,3) (-2 + 6)/2 = 2 .'. x = 2 is the axis of symmetry. Length of latus rectum is 4a units (easily proven) 4a = 6+|-2| = 8 a = 2 y-coordinate of the vertex can be either 3-2 = 1 or 3+2 = 5 (x-2)^2 = 8(y-1) or/ (x-2)^2 = -8(y-5)
End points are (-2,3) and (6,3) (-2 + 6)/2 = 2 .'. x = 2 is the axis of symmetry. Length of latus rectum is 4a units (easily proven) 4a = 6+|-2| = 8 a = 2 y-coordinate of the vertex can be either 3-2 = 1 or 3+2 = 5 (x-2)^2 = 8(y-1) or/ (x-2)^2 = -8(y-5)
L Lukybear Active Member Joined May 6, 2008 Messages 1,466 Gender Male HSC 2010 Nov 6, 2009 #3 gurmies said: Length of latus rectum is 4a units (easily proven) Click to expand... Whats the proof?
ninetypercent ninety ninety ninety Joined May 23, 2009 Messages 2,146 Location Sydney Gender Female HSC 2010 Nov 6, 2009 #4 latus rectum has the equation y = a equation of parabola x^2 = 4ay substitute y = a for y x^2 = 4a^2 x = +/- 2a therefore, the length of the latus recturm is 2a + 2a = 4a units
latus rectum has the equation y = a equation of parabola x^2 = 4ay substitute y = a for y x^2 = 4a^2 x = +/- 2a therefore, the length of the latus recturm is 2a + 2a = 4a units
L Lukybear Active Member Joined May 6, 2008 Messages 1,466 Gender Male HSC 2010 Nov 6, 2009 #5 nvm EDIT: Thanxs anywaz.
M mtsmahia Member Joined Jun 21, 2008 Messages 284 Gender Male HSC 2010 Nov 7, 2009 #6 so the length of the latus rectum for any parabola is 4a right?
jet Banned Joined Jan 4, 2007 Messages 3,148 Gender Male HSC 2009 Nov 7, 2009 #7 Always. It's a property of the parabola.