Math EXT 1 Question help (1 Viewer)

[Farhanthestudent005]

Will appreciate if someone could help...thanks

 

[cossine]

View attachment 35695
Will appreciate if someone could help...thanks

Use the theorem ln(f(x)) d/dx = f'(x)/f(x) # You can prove this through chain rule

 

[Trebla]

Making x the subject gives x = 0.5*(u+1) so dx = 0.5*du. Substitute for x, dx and change the limits accordingly and it should reduce to a simpler integral.

 

[chilli 412]

View attachment 35695
Will appreciate if someone could help...thanks

hope this helps

 

[Farhanthestudent005]

hope this helps

Yes, it helps me thank you very much. Although I forgot one thing, why do the bounds change again?

 

[chilli 412]

Yes, it helps me thank you very much. Although I forgot one thing, why do the bounds change again?

so pretty much we did a u-sub, and what i did was this:
i let u = 2x-1
now my original integral had the bounds from 1 to 2
so when i did a u-sub here, i have to now say that my 'new' upper bound will be 2x-1, where 'x' was my old upper bound. So now i get a new upper bound as 2(2) - 1 = 3
i do the same to my old lower bound, and i get 2(1) - 1 = 1 , hope that helps