maths question on functions (1 Viewer)

Aznmichael92

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hello all, i am not sure if this function is odd or even. Can you explain why it is which?

x/(x^2 - 1)
 

lyounamu

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Aznmichael92 said:
hello all, i am not sure if this function is odd or even. Can you explain why it is which?

x/(x^2 - 1)
The best way to see whether it is even or odd is to do the test like this:

if f(-x) = f(x), it is even
if f(-x) = -f(x), it is odd
if f(-x) =/= f(x) & -f(x), it is neither

f(x) = x/(x^2-1)
f(-x) = -x/((-x)^2-1)
= -x/((x^2-1)
= -f(x)
Therefore, the function is odd.
 

Aznmichael92

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lyounamu said:
The best way to see whether it is even or odd is to do the test like this:

if f(-x) = f(x), it is even
if f(-x) = -f(x), it is odd
if f(-x) =/= f(x) & -f(x), it is neither

f(x) = x/(x^2-1)
f(-x) = -x/((-x)^2-1)
= -x/((x^2-1)
= -f(x)
Therefore, the function is odd.
thank you very much :D
 

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