A Aznmichael92 Member Joined May 27, 2008 Messages 520 Gender Male HSC 2010 Sep 30, 2008 #1 hello all, i am not sure if this function is odd or even. Can you explain why it is which? x/(x^2 - 1)
hello all, i am not sure if this function is odd or even. Can you explain why it is which? x/(x^2 - 1)
lyounamu Reborn Joined Oct 28, 2007 Messages 9,998 Gender Male HSC N/A Sep 30, 2008 #2 Aznmichael92 said: hello all, i am not sure if this function is odd or even. Can you explain why it is which? x/(x^2 - 1) Click to expand... The best way to see whether it is even or odd is to do the test like this: if f(-x) = f(x), it is even if f(-x) = -f(x), it is odd if f(-x) =/= f(x) & -f(x), it is neither f(x) = x/(x^2-1) f(-x) = -x/((-x)^2-1) = -x/((x^2-1) = -f(x) Therefore, the function is odd.
Aznmichael92 said: hello all, i am not sure if this function is odd or even. Can you explain why it is which? x/(x^2 - 1) Click to expand... The best way to see whether it is even or odd is to do the test like this: if f(-x) = f(x), it is even if f(-x) = -f(x), it is odd if f(-x) =/= f(x) & -f(x), it is neither f(x) = x/(x^2-1) f(-x) = -x/((-x)^2-1) = -x/((x^2-1) = -f(x) Therefore, the function is odd.
A Aznmichael92 Member Joined May 27, 2008 Messages 520 Gender Male HSC 2010 Sep 30, 2008 #3 lyounamu said: The best way to see whether it is even or odd is to do the test like this: if f(-x) = f(x), it is even if f(-x) = -f(x), it is odd if f(-x) =/= f(x) & -f(x), it is neither f(x) = x/(x^2-1) f(-x) = -x/((-x)^2-1) = -x/((x^2-1) = -f(x) Therefore, the function is odd. Click to expand... thank you very much
lyounamu said: The best way to see whether it is even or odd is to do the test like this: if f(-x) = f(x), it is even if f(-x) = -f(x), it is odd if f(-x) =/= f(x) & -f(x), it is neither f(x) = x/(x^2-1) f(-x) = -x/((-x)^2-1) = -x/((x^2-1) = -f(x) Therefore, the function is odd. Click to expand... thank you very much