mmm (1 Viewer)

1zephyr · Sep 29, 2014

simplify
(sinA/cosA+sinA)+(sinA/cosA-sinA)

integral95 · Sep 29, 2014

1zephyr said:
simplify
(sinA/cosA+sinA)+(sinA/cosA-sinA)

$LHS = \frac{sinA}{cosA+sinA}+ \frac{sinA}{cosA-sinA} = \frac{sinA(cosA-sinA+cosA+sinA)}{\cos^2A-\sin^2A} = \frac{2sinAcosA}{\cos^2A-\sin^2A} = \frac{sin2A}{cos2A} \\ \\ tan2A$

1zephyr · Sep 29, 2014

cheers me brahsss

Speed6 · Sep 29, 2014

1zephyr said:
cheers me brahsss

da faq.

mmm (1 Viewer)

1zephyr

Member

integral95

Well-Known Member

1zephyr

Member

Speed6

Retired '16

Users Who Are Viewing This Thread (Users: 0, Guests: 1)