Moments Question (1 Viewer)

D94

New Member
Joined
Oct 5, 2011
Messages
4,424
Gender
Male
HSC
N/A
What you can do is split the force into vertical and horizontal components. The vertical component is 200sin(30) (down) and the horizontal component is 200cos(30) (left).

As with all moments, the sum of moments is the the sum of (Force x Perpendicular Distance), so the vertical force acts downwards and is 50mm from the pivot, and the horizontal force acts leftwards and is 150mm from the pivot.

The answer is 21 Nm.
 

astroman

Well-Known Member
Joined
May 12, 2014
Messages
7,085
Location
Las Vegas
Gender
Male
HSC
2015
Sum of positive moments clockwise (pivot) = -(200cos30 x 0.15) + (200sin30 x 0.05)
= -20.98Nm
= 21NM
A
 
Last edited:

Apdo

New Member
Joined
Sep 2, 2014
Messages
7
Gender
Male
HSC
2015
Yeah I got the question wrong first because I thought I was calculating an unknown force, but it's just summing that force around the fulcrum :smile:
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top