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Individui Superiore
Who is confident with bullshit like this-
$15000 borrowed at 12% p.a., money payed back at monthly intervals over 5 yrs. Find the monthly installment.
I kinda get how to do it- but as u can see it is a long method-
Let 'm' be the monthly payment
n = 5 x 12 = 60 months
monthly interest = 1 %
After 1 Month>
A1= 15000(1+1/100)^1 - M
= 15000(1.01)^1 - M
A2= A1(1.01)^1 - M
= [15000(1.01)^1 - M](1.01) - M
= 15000(1.01)^2 - M(1.01+1)
A3= A2(1.01) - M
= [15000(1.01)^2 - M(1.01+1)](1.01)- M
= 15000(1.01)^3 - M(1.01^2 + 1.01 +1)
A60= 15000(1.01^60- M(1+1.01+1.01^2+1.01^3+...1.01^59) (Latter part is our geo series with a=1, r= 1.01 and n=60)
Sum of series-
S60= 1(1.01^60-1)/(1.01-1)
Therefore, A60 = 15000(1.01^60- M(1(1.01^60-1)/(1.01-1))
If loan is repaid after 60 months, then A60 = 0
therefore,
15000(1.01^60- M(1(1.01^60-1)/(1.01-1))=0
M(1(1.01^60-1)/(1.01-1))= 15000(1.01)^60
Finally,
M= 15000(1.01)^60(0.01/(1.01^60 -1))
Therefore the monthly repayment is $333.67 or $334 dollars.
Fucking long and confusing
There is a much quicker way using the formula-
PR^n = Q(R^n -1)/(R-1) where Q is the 'installment' but it looks as though we need to know how to do these questions with a geometric series appraoach. Praying we dont get one this yr!!!
$15000 borrowed at 12% p.a., money payed back at monthly intervals over 5 yrs. Find the monthly installment.
I kinda get how to do it- but as u can see it is a long method-
Let 'm' be the monthly payment
n = 5 x 12 = 60 months
monthly interest = 1 %
After 1 Month>
A1= 15000(1+1/100)^1 - M
= 15000(1.01)^1 - M
A2= A1(1.01)^1 - M
= [15000(1.01)^1 - M](1.01) - M
= 15000(1.01)^2 - M(1.01+1)
A3= A2(1.01) - M
= [15000(1.01)^2 - M(1.01+1)](1.01)- M
= 15000(1.01)^3 - M(1.01^2 + 1.01 +1)
A60= 15000(1.01^60- M(1+1.01+1.01^2+1.01^3+...1.01^59) (Latter part is our geo series with a=1, r= 1.01 and n=60)
Sum of series-
S60= 1(1.01^60-1)/(1.01-1)
Therefore, A60 = 15000(1.01^60- M(1(1.01^60-1)/(1.01-1))
If loan is repaid after 60 months, then A60 = 0
therefore,
15000(1.01^60- M(1(1.01^60-1)/(1.01-1))=0
M(1(1.01^60-1)/(1.01-1))= 15000(1.01)^60
Finally,
M= 15000(1.01)^60(0.01/(1.01^60 -1))
Therefore the monthly repayment is $333.67 or $334 dollars.
Fucking long and confusing
There is a much quicker way using the formula-
PR^n = Q(R^n -1)/(R-1) where Q is the 'installment' but it looks as though we need to know how to do these questions with a geometric series appraoach. Praying we dont get one this yr!!!