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Multiple choice-Q14 (1 Viewer)

Answer to Q14 multi

  • a)

    Votes: 3 2.3%
  • b)

    Votes: 60 45.1%
  • c)

    Votes: 53 39.8%
  • d)

    Votes: 17 12.8%

  • Total voters
    133

dp624

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Aaron Judd that's bs
I know Mrs Pooviah and she aint that dumb
 

dp624

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Aaron.Judd said:
Exactly, she's super smart. Hence it is C.
I don;'t f*cking think so you troll. Retard i go to JRAHS and you certainly don't
 

Mark576

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yeah I put (b). the question is pretty standard
 

Aaron.Judd

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The answer is C. d9684 pm me, tell me who you are and if I like you I'll reveal my identity proving I do (or did) go to JRAHS.
 

iEdd

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Yes, we already know that you think that there is no such thing as diluting acids. You think the answer is C, because you believe if I put one drop of HCl in a pool, the pH of the whole pool will be 1. Actually, let's make a similar actual question:

100mL of 1M HCl is added to a 50 000L swimming pool. What is the pH of the final solution?

b) pH=5.7, as H+ concentration was calculated in 50L
c) pH=1, as there were that many H+ ions in the original 100mL

Let me guess, Mrs Pooviah says it's C?
 

dp624

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Aaron.Judd said:
The answer is C. d9684 pm me, tell me who you are and if I like you I'll reveal my identity proving I do (or did) go to JRAHS.
PM'ed
 

drobby

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Kearnzo said:
n(H+ in HCl)= 0.02 x 0.08 = 1.6x10^-3

n(OH- in NaOH)= 0.03 x 0.05 = 1.5x10^-3

That is right

But 0.0016 - 0.0015 is 0.0001

This is number of moles of H+ ions left in the solutions

Ph = -log10[H+]

c = n/v

volume is 20mls +30 mls = 0.05 L

therefore [H+] is 0.0001/0.05 = 0.002

Ph = -log10[0.002] is equal to 2.69... = 2.7
did the same and got c
 

eddy11

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its C, i initially put B but its painfully obvious its C having realised that i forgot to caculate the [H+] and rather just the number of moles of H+ ions.
 

iEdd

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Um, swap where you said B and C.

C is what you put if you forget to find concentration.
 

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