MedVision ad

Parabolas (1 Viewer)

Boonyak

Member
Joined
Feb 15, 2012
Messages
222
Gender
Male
HSC
2012
Hey guys i need to remember how sketching parabolas works like x^2-1 is one down etc like when is it to the right 1 up and stuff :) cheers. and how do i sketch something thats in terms of x for eg x=y^3

Thanks in advanced
 

deswa1

Well-Known Member
Joined
Jul 12, 2011
Messages
2,256
Gender
Male
HSC
2012
With a lot of these, the easiest way is to graph the original function and then test a few points. For example, with y=x^2-1, it is clear that for every value of x, y=x^2-1 will be one less than y=x^2. Therefore you just shift the graph down one unit. When you do a few of them, you will be able to tell the translation very quickly...

To sketch something like x=y^3, note that it is the same thing as y=x^(1/3) so you can just sketch that.
 

Timske

Sequential
Joined
Nov 23, 2011
Messages
794
Gender
Male
HSC
2012
Uni Grad
2016
are you learning inverse boonyak?
 

RealiseNothing

what is that?It is Cowpea
Joined
Jul 10, 2011
Messages
4,591
Location
Sydney
Gender
Male
HSC
2013
Pretty sure you can just sketch y = x^3 then rotate it 90 degress clockwise.
 

bleakarcher

Active Member
Joined
Jul 8, 2011
Messages
1,509
Gender
Male
HSC
2013
just reflect y=x^3 about the line y=x to obtain the graph of y=x^(1/3).
 

SpiralFlex

Well-Known Member
Joined
Dec 18, 2010
Messages
6,960
Gender
Female
HSC
N/A
Note: This is posted in 2U though. They don't do inverses.
 

Boonyak

Member
Joined
Feb 15, 2012
Messages
222
Gender
Male
HSC
2012
Thanks spiral lol was stressing say wtf is inverse ehehe .
 

SpiralFlex

Well-Known Member
Joined
Dec 18, 2010
Messages
6,960
Gender
Female
HSC
N/A
Some notable things, but nothing else you really need to know about this graph. Just note:

- As x values get larger, the corresponding ordinates get larger.

- Similarly as x values get smaller, the corresponding ordinates get smaller.

- There is a vertical tangent at x = 0. (This is beyond the scope of 2U)

But in 2U maths, we have found that for stationary points, the tangents will be parallel to the x axis. Hence horizontal. (Gradient 0)

What if we could find vertical tangents? Well we know a straight line parallel to the y axis has an undefined gradient, so dy/dx=undefined.





For vertical tangents, y'=undefined.



When ,

Hence there is a vertical tangent at the origin.


Now, if you were to draw this, it will be flat near the origin then diverge out very quickly! Have a go at graphing it!
 

nahi11

Member
Joined
Mar 28, 2011
Messages
131
Gender
Male
HSC
2012
If ever in doubt just test a few points. It can save you a few marks. After testing about three points you should be able to sketch the graph.

EDIT: How do you guys change from normal text to the 'natural math' text? ie what Spiral has done in the post above me.
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top