parametric representation help!! (1 Viewer)

[viraj30]

given the parabola 2x^2= y, for what values of m does the line y=m(x+1) have two points of intersection?

Thnx for help!

 

[bleakarcher]

y=2x^2
y=m(x+1)
When line and curve intersect,
m(x+1)=2x^2
2x^2-mx-m=0
Discriminant=m^2-4(2)(-m)=m^2+8m
In order for there to be two points of intersection the discriminant must be greater than 0. Hence:
m^2+8m>0
Therefore, m<-8 or m>0