perms help pls (1 Viewer)

=)(= · Sep 12, 2022

How you u get iii kinda lost

Life'sHard · Sep 13, 2022

Minus the "no restrictions" case from the case where all the A's are together.
Been a while but I think it should be:

$\frac{11!}{2!\cdot 3! \cdot 2!}-\frac{9!}{2!\cdot 2!}$

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perms help pls (1 Viewer)

=)(=

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Life'sHard

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