Permutation (1 Viewer)

[crex]

Q) 3,3,4,4,4 and 5 are placed in a row to form a 6 digit number. How many possible combinations there are if the number formed is even.

Is the answer this ? (5! x 3)/(2! x 2!) = 90

Thanks

 

[hit patel]

5!/(3!x2!)
Therefore 10.

 

[RealiseNothing]

 

[crex]

right makes sense now

thx