Run hard@thehsc
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Phys q on kepler (1 Viewer)
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Run hard@thehsc
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Can someone explain the reasoning behind this - the derivation is straight forward
ExtremelyBoredUser
Bored Uni Student
reasoning for what? Do you want to see how it is solved?
ExtremelyBoredUser
Bored Uni Student
excuse my paint.net artistry
periapsis is the position which has the least distance between the focus and itself. consequently this is a - c.
apoapsis is the position which has the most distance between the focus and itself. this is a + c
e = c/a (eccentricity)
r_p = a - ea = a(1-e)
r_a = a + ea = a(1+e)
, r_{a} = a(1+e) )
and the ratio of p to a is simply Rp/Ra
If you want reasoning how the radius equation is found
periapsis is the position which has the least distance between the focus and itself. consequently this is a - c.
apoapsis is the position which has the most distance between the focus and itself. this is a + c
e = c/a (eccentricity)
r_p = a - ea = a(1-e)
r_a = a + ea = a(1+e)
and the ratio of p to a is simply Rp/Ra
If you want reasoning how the radius equation is found
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Run hard@thehsc
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@ExtremelyBoredUser thanks man - was straight forward - was just confused if it was just this alone or not