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Physics 2004 HSC Exam (1 Viewer)

S13WPN

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Hey, has anyone got the multiple choice answers or attempted to do some of the questions for study? Thanks
 

speed2

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multiple choice answers are on Board of Studies
 

S13WPN

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thanks mate, i just found them... and went alright too :)
 
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what do u get?

In the success one Core option topic multiple choice i usually get 17-18/20
 

gordo

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out of interest wat was the answer for the induction coil breaks on the train

something like that in the mc

i remember a big argument on BOS after the exam
 

rama_v

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gordo said:
out of interest wat was the answer for the induction coil breaks on the train

something like that in the mc

i remember a big argument on BOS after the exam
The answer was induction motor (C I think)
Its the only one it could be.
 

S13WPN

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DigitalFortress said:
what do u get?

In the success one Core option topic multiple choice i usually get 17-18/20
i got 12/15... pretty good for me coz i only got 57% in the trial, which was an improvement on the half yearly as well :p

gordo said:
out of interest wat was the answer for the induction coil breaks on the train

something like that in the mc

i remember a big argument on BOS after the exam
yeh there was a diagram of part of a train but the question was just about what other devices use the same law of conservation of energy in the same way - rama_v got it right
 

S13WPN

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peeasoup said:
Of course its the fucking cooktop. Why the fuck is there even a thread on this question. Its so plain and simple. If you put motors, your a brainless moron who doesnt know shit.
bwahahaha :D:D:D

 
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Has anyone got the answers to the rest of the test paper?? It would be much appreciated if you post em up.
 
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This is just what I have gotten for the first few questions after the multiple choice (haven't done the rest yet). Not sure if they are right though

16) range = 220.92m

17)a.i 2.148 *10^10
ii. 9.15 * 10^-7 m/s

I think I stuffed up this question - especially ii

b. The equation for orbital velocuty is: v = (2Gm/r^2)^.5
where m is the weight of the moon. As the weight does not appear in this equation, the change in weight of the satelite will have no effect on the velocity. As there is a set velocity with each alititude, the satellite will remain at constant alitidue


sorry - not really much to go on
 

physician

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chinesefireball ur answer to question 16 is correct

although 17 is incorrect

for ( i ) u need to use Kepler's Law

r3/T2=Gm/4pi2

i Got this wrong the first time because i was using r2 instead of r3... hehe

the answer is 7.351 * 1022 kg

as for ( ii )... success uses the formula v= (sqaure root) Gm/r

I thought the formula had a 2 before the Gm... I don't know... but neways
the answer to ( ii ) is 1628 m/s = 1.63 km/s

and yeh ur answer to ( b ) is correct
 
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Jago

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orbital velocity is v= (sqaure root) Gm/r

escape velocity has the 2 before the Gm
 
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Thanks for that - it would be nice if bos would be able to give us the actual answers (well at least the maths answers anyway)
 

rama_v

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Remeber also that all objects fall at the same rate regardless of mass, neglecting air resistnace. Therefore a 100 kg anvil will fall at the same rate as a 1 g feather. Both will have the same impact velocty when dropped from the same height.

Also remember that satellites that are in orbit are perpetually falling back towards the moon, or earth, or whatever planet they are orbiting. Hence a change in mass will not affect the rate at which the satallite is falling, hence the oribital velocty is not affected.
 

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