physics exam (1 Viewer)

mzduxx2006

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farahodish said:
why THE F#$$ would it say .37%?! THATS SO NEGLIGIBLE THAT ITS NOT EVEN FUNNY!!!!!!!

swear you're all seeing things. *curls up into denial bubble*

AND F%#@ AT THE DIAMETER/RADIUS BUSINESS

ARE YOU TESTING EFFING PHYSICS, OR FREAKING READING SKILLS WITH THAT QUESTION?!?!?!?!?!?!?

TEST YOUR EFFING SUBJECT!!

IF I WANTED TO SIT AN EXAM THAT TESTED ME ON MY EFFING ABILITIES TO NOTICE THINGS LIKE THAT I"D SIT AN EFFING IQ TEST!!!!!!!!!!!!

*BOMBS
WHOEVER
WROTE
PHYSICS
EXAM'S
FAMILY
..
..
..
MULTIPLE TIMES*

grrrrrrrrrrrrrrrrrrrr :burn: :burn:
omg can i assist?
 

fuzzyfaction89

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Hey all. Physics wasn't too bad - definetly way more calculations than in previous years.


What you all get for multiple choice?
1) A
2) A
3) B
4) D
5) D
6) D
7) C
8) C (apparently it's D - How can you tell?)
9) C
10) B (Lol, I wasn't sure about this - most people seem to think it's reflection though)
11) D
12) A
13) C (right hand palmzor rule)
14) C (It's meant to be A, because the question says 'property' ...)
15) A
 
G

gaoOO

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fuzzyfaction89 said:
8) C (apparently it's D - How can you tell?)
emf = - magnetic flux/time

i got a couple of the multiple choice wrong i think, looking at everyone else's answers.


i think i stuffed all the calculation questions, which makes no sense since it's usually the maths part of physics that pulls my mark up.

some parts were difficult, but overall, i thought it was a pretty decent paper
 

lil dynamyt

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I screwed up this exam so badly. The calculations were so confusing. I think ill get around a 50-60 raw mark...
 

mhhmhh

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peoplez... i have the paper and it clearly says 0.37% = 0.0037 just to clarify ur mysteries
 

wu89

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realisation has just dawned on me that i changed 4 correct multiple choice answers to 4 incorrect ones.
wooooooooooooooooooooooooooooooooooooot.
and that i also looked at group 5 on periodic table and assumed in the spur of the moment that it was group 3. hence my phosphorus answer for 14.
yay!
can't wait for the 19/12...
 

nounderscore

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Shrikar said:
I used V^2 = U^2 +2aY
Where v= 0 at the top
U = ?
a = 9.8
Y = 110 (80+30)

Found U, then subed it into

v= u + at

Found time

Subed it into

X = U(x) X t

were X = 92 cm

T is known
U(x)= to be calculated

therefore u(x) = 19.8 ms-1
dude.. your values are all in cm yet your answer is is m.. if you used 1.1 and 0.92 respectively, you would have got 1.98ms-1.. which is what i got :)

hahah howd you guys do the geostationary one.. it said.. the satellite is yet to be launched, then asked its height. i drew an arrow to the satellite is yet to be launched and stated h = 0 .. hahha gg
 

macca007

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The horizontal velocity at the bottom of the track at P, use the equation v=u+at to get time by s=ut+0.5at^2, and u get velocity a=9.8, easy as.

Also in the p-type silicon doped with boron??? coz it has 3 valence electrons phosphorus has 5,
anyway ova it and need to get drunk
 

Alex.

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lol that physics exam wasn't too bad i rekon i can get band 6 (I HOPE)

neway i dont understand y a few ppl are saying 14 is not c) and is in fact a). Im 100% sure i remember my teacher saying that, although semi-conductors are doped with extra electrons/holes, that it is still NEUTRAL ie. they are neither positive nor negative and i also read it on a sheet. So I definitely think its 14c).
 
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mitch0816

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farahodish said:
and ohmygosh at the freaking radius/satellite thingo..
I FORGOT THAT KEPLER"S LAW EVEN EXISTED?!
so i just said that a geostationary orbit is usuall 35800km and subtracted the other number from it.
which is wrong but LOL
yeah i think u r wrong. a geostationary satellite orbits at a height of 35800 odd kilometres, thats not its distance from the Earth's centre of gravity. so if you took 35800 and subtracted the other number then you would've gotten a height less than that of a geostationary orbit.

what i did was take the equation:
r3/T2 = Gm/4π2
we know that T = 24 hours = 86400 seconds
we know that m = mass of Earth = 6×1024 kg
we know that G = 6.67×10-11
manipulate the equation to make:
r = 3√[T2×(Gm/4π2)]
r = 42,297,523.87 m
now with this you find the height:
h = r - rE
h = 42,297,523.87 - (6.373×106) [it was somewhere around that anyway]
h = 35,924,523.87 m
h = 35,924.52 km
h = 3.592×104 km

that's what i did anyways.
 

twilight1412

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nounderscore said:
dude.. your values are all in cm yet your answer is is m.. if you used 1.1 and 0.92 respectively, you would have got 1.98ms-1.. which is what i got :)

hahah howd you guys do the geostationary one.. it said.. the satellite is yet to be launched, then asked its height. i drew an arrow to the satellite is yet to be launched and stated h = 0 .. hahha gg
keplers law solves this
also alex is right
although they are doped they are electrically neutral unless they meet with a ptype semiconductor
and ptype = positive = holes = group 3 = boron
 

Forbidden.

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kaylee_89 said:
man.. screw tht.. so F'n hard!!! screw loose!!
mitch0816 said:
yeah i think u r wrong. a geostationary satellite orbits at a height of 35800 odd kilometres, thats not its distance from the Earth's centre of gravity. so if you took 35800 and subtracted the other number then you would've gotten a height less than that of a geostationary orbit.

what i did was take the equation:
r3/T2 = Gm/4π2
we know that T = 24 hours = 86400 seconds
we know that m = mass of Earth = 6×1024 kg
we know that G = 6.67×10-11
manipulate the equation to make:
r = 3√[T2×(Gm/4π2)]
r = 42,297,523.87 m
now with this you find the height:
h = r - rE
h = 42,297,523.87 - (6.373×106) [it was somewhere around that anyway]
h = 35,924,523.87 m
h = 35,924.52 km
h = 3.592×104 km

that's what i did anyways.
i love you both
 

simplistic

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oh the depression , daym physics exam it ruined my whole end of hsc mood !!!
i cant even party without feeling guilty!!
dam dam daaaaaaaaaam
 

Shrikar

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simplistic said:
oh the depression , daym physics exam it ruined my whole end of hsc mood !!!
i cant even party without feeling guilty!!
dam dam daaaaaaaaaam
lol, i know exactly, how you feel.
 

ballin

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ok just want to know how i went for the calculations compared to you guys...

grrr for the projectile i gave the answer in m/s but my units were actually cm gay

i pretty sure i got the height of the satellite right... use kep's law get like 35 900 km

freaking velocity of that particle... i read it as 37% instead of 0.37% grrr

i got 196 turns ...and the mass was on X and exerted a torque of T = Fd where F = mg and d = 0.1 and for the electric field intensity i said like something around 1700 NC - 1 but did we have to provide direction also?
and also for the drawing with the electric plates, i just drew curved field lines emanating from the positive plate and joining the negative cylinder...??

the gradient at the end of the graph was like 3
 

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