Paradoxica
-insert title here-
I just hit a key combo and whatever Unicode Symbol I want appears.
Customisation is da best )))))
Customisation is da best )))))
Ans are (for v=v(x))Some more motion questions:
Motion defined by v=v(x)
1.The velocity of a body is given by v=〖(cos(x^2)x)/(1+sinxcosx).〗find the value of t when x=π/4 if P starts from the origin
2.The velocity of a particle moving on the x-axis is given by v= (squareroot of sinx) e^(x/2), 0≤x≤pi/3, where x is the displacement of the particle from the origin
a.Show that the acceleration of the particle in terms of its displacement can be expressed by a=1/2 e^(-x) (cosx-sinx)
b.Hence find the displacement of the particle at which the maximum speed occurs
3.A particle moves in a straight line. At time t seconds its displacement is x metres from a fixed point O on the line, its acceleration is a m/s^2 and its velocity is v m/s where v is given by 32/x – x/2. The particle starts 2 metres to the right O
a.Find an expression for a in terms of x
b.Show that t=ꭍ2x/(64-x^2) dx and hence show that x^2=64-60e^(-t)
c.Sketch the graph x^2 against t and describe the limiting behaviour of the particle
Motion defined by a=a(x)
1.The acceleration of a particle in a straight line is given by x’’=-2e^(-x) where x m is the displacement from the origin . Initially the particle is at the origin with velocity 2 m/s
a.Prove that v=2e〖^(-x/2)〗
b.What happens to v as x increase without bound?
2.The acceleration of a body moving along a straight line is given by:
(d^2 x)/(dt^2 )=-24/(x^2)
Where x is the displacement from the origin after t seconds. When t=0 the body is 3 metres to the right of the origin with a velocity of 4m/s
a.Show that the velocity, v, of the body in terms of x is given by v= 4squareroot of 3/ squar root of x
b.Find an expression for t in terms of x
c.How long does it take for the body to reach a point 10m to the right of the origin?
3.A particle P moves in the straight line XOX’ so that its acceleration x’’ when its displacement from 0 is x, is given by x’’= 1/squareroot (4-x^2) + 1/(9+x^2) and hence, if P is projected from O with velocity squareroot of pi, prove that 1/2v^2= (inverse of sin) x/2+1/3tan(inverse)x/3 + pi/2. Find (in terms of pi), the speed of the particle when it is squareroot of 3 units on the
a.Positive
b.Negative side of 0
Leehuan/Integrand/David need your help
autohotkey?I just hit a key combo and whatever Unicode Symbol I want appears.
Customisation is da best )))))
Some more motion questions:
Motion defined by v=v(x)
1.The velocity of a body is given by v=〖(cos(x^2)x)/(1+sinxcosx).〗find the value of t when x=π/4 if P starts from the origin
cos squared x
The question says to find the value of t and your answer has a value for x?Ans are (for v=v(x))
1. x=3
2. max occurs when a=0, e^x/2(cosx-sinx)=0...tanx=1,...x=pi/4
3. a. x''=-1024/(x^3) = pi/4
b. the particle slows down to x=8
a=a(x)
1.a. v=2e^(-x/2)
b. v approaches 0 (as in v arrow 0)
3. a. 4squrroot of pi/3
b. Squreroot of 2pi/3
How much progress have you made on any of those questions yourself?Some more motion questions:
Motion defined by v=v(x)
1.The velocity of a body is given by v=〖(cos(x^2)x)/(1+sinxcosx).〗find the value of t when x=π/4 if P starts from the origin
2.The velocity of a particle moving on the x-axis is given by v= (squareroot of sinx) e^(x/2), 0≤x≤pi/3, where x is the displacement of the particle from the origin
a.Show that the acceleration of the particle in terms of its displacement can be expressed by a=1/2 e^(-x) (cosx-sinx)
b.Hence find the displacement of the particle at which the maximum speed occurs
3.A particle moves in a straight line. At time t seconds its displacement is x metres from a fixed point O on the line, its acceleration is a m/s^2 and its velocity is v m/s where v is given by 32/x – x/2. The particle starts 2 metres to the right O
a.Find an expression for a in terms of x
b.Show that t=ꭍ2x/(64-x^2) dx and hence show that x^2=64-60e^(-t)
c.Sketch the graph x^2 against t and describe the limiting behaviour of the particle
Motion defined by a=a(x)
1.The acceleration of a particle in a straight line is given by x’’=-2e^(-x) where x m is the displacement from the origin . Initially the particle is at the origin with velocity 2 m/s
a.Prove that v=2e〖^(-x/2)〗
b.What happens to v as x increase without bound?
2.The acceleration of a body moving along a straight line is given by:
(d^2 x)/(dt^2 )=-24/(x^2)
Where x is the displacement from the origin after t seconds. When t=0 the body is 3 metres to the right of the origin with a velocity of 4m/s
a.Show that the velocity, v, of the body in terms of x is given by v= 4squareroot of 3/ squar root of x
b.Find an expression for t in terms of x
c.How long does it take for the body to reach a point 10m to the right of the origin?
3.A particle P moves in the straight line XOX’ so that its acceleration x’’ when its displacement from 0 is x, is given by x’’= 1/squareroot (4-x^2) + 1/(9+x^2) and hence, if P is projected from O with velocity squareroot of pi, prove that 1/2v^2= (inverse of sin) x/2+1/3tan(inverse)x/3 + pi/2. Find (in terms of pi), the speed of the particle when it is squareroot of 3 units on the
a.Positive
b.Negative side of 0
Leehuan/Integrand/David need your help
not much...I'm trying to self learn the topic and its quite hard lolHow much progress have you made on any of those questions yourself?
Okay leehuan sozCan you please not just throw like 10 questions at once... and maybe at most THREE PARTS at a time
I have to attend my uni classes as well you know... looking at all of that I'm just like ok I have a bit of free time now which question do I even answer
I think i looked at the wrong answers. Could you help me Shuuya, it'd be greatly appreciatedThe question says to find the value of t and your answer has a value for x?
Have you asked your teacher (or tutor if you go tutoring) for help with them?not much...I'm trying to self learn the topic and its quite hard lol
Oi Nailgun how is this handwriting not feminine.
it's gonna be too many q's for them and they'll get pissed ( I think)Have you asked your teacher (or tutor if you go tutoring) for help with them?
Here's the thing it's also too many questions for us.it's gonna be too many q's for them and they'll get pissed ( I think)
stop harrassing ShuuyaOi Nailgun how is this handwriting not feminine.