Green Yoda
Hi Φ
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help:
prove that
(sin^2(a)*cos^2(b))-(cos^2(a)*sin^2(b))=sin^2(a)-sin^2(b)
prove that
(sin^2(a)*cos^2(b))-(cos^2(a)*sin^2(b))=sin^2(a)-sin^2(b)
help:
prove that
(sin^2(a)*cos^2(b))-(cos^2(a)*sin^2(b))=sin^2(a)-sin^2(b)
bruh this is purely 2u yr 11 trig.......I dunno differentiation yet lol
Yes. (Sorry, forgot this was in prelim thread and you hadn't learnt calculus yet.)bruh this is purely 2u yr 11 trig.......I dunno differentiation yet lol
Can you do it another way?
bruh this is purely 2u yr 11 trig.......I dunno differentiation yet lol
Can you do it another way?
help:
prove that
(sin^2(a)*cos^2(b))-(cos^2(a)*sin^2(b))=sin^2(a)-sin^2(b)
What does Q.E.D stand for?my pleb working
In Latin, it translates into quod erat demonstrandum, meaning "which is what had to be proven". It's mainly used in the end of a mathematical proofWhat does Q.E.D stand for?
QED is an abbreviation of the Latin words "Quod Erat Demonstrandum" which loosely translated means "that which was to be demonstrated". It is usually placed at the end of a mathematical proof to indicate that the proof is complete.What does Q.E.D stand for?
Unless there's something I'm missing, isn't it just 23,246,692*(1+0.0114) = 23511704.3, and since you can't have 0.3 of a person, the answer is 23,511,704If in 2014, the Australias population was 23 246 692, with a growth rate of approximately 1.14%, what was the population in 2015?
Please help! What is the formula and how would you work out this question
cos^2 = 1 - sin^2 and you are doneHelp:
prove sin^2(θ)tan(θ)+cos^2(θ)cot(θ)+2sin(θ)cos(θ) = tan(θ)+cot(θ)
My working out so far:
LHS=(1-cos^2(θ))tan(θ)+cos^2(θ)cot(θ)+2sin(θ)cos(θ)
=tan(θ)-sin(θ)cos(θ)+cos^2(θ)cot(θ)+2sin(θ)cos(θ)
=tan(θ)+cos^2(θ)cot(θ)+sin(θ)cos(θ)
You're almost there. Continuing on:Help:
prove sin^2(θ)tan(θ)+cos^2(θ)cot(θ)+2sin(θ)cos(θ) = tan(θ)+cot(θ)
My working out so far:
LHS=(1-cos^2(θ))tan(θ)+cos^2(θ)cot(θ)+2sin(θ)cos(θ)
=tan(θ)-sin(θ)cos(θ)+cos^2(θ)cot(θ)+2sin(θ)cos(θ)
=tan(θ)+cos^2(θ)cot(θ)+sin(θ)cos(θ)
You mean in terms of tan(θ), right?help:
express tan(3θ) in terms of θ
Thats what I did but the textbook wants it in Just θ....You mean in terms of tan(θ), right?
Well it is already in terms of θ.Thats what I did but the textbook wants it in Just θ....