W Wonder Member Joined May 11, 2012 Messages 101 Gender Female HSC 2014 Jul 3, 2012 #1 From Cambridge Year 11 3U, Exercise 8A (Not the explain part, just part d.) Thanks in advance!
iBibah Well-Known Member Joined Jun 13, 2012 Messages 1,374 Gender Male HSC 2013 Jul 3, 2012 #2 f(-2)=1 f(x)=ax(x-0) - Only passes through x axis at origin =ax^2 f'(x)=2ax f'(-2)=2(-2)a=1 a=-1/4 therefore f(x)=-1/4x^2
f(-2)=1 f(x)=ax(x-0) - Only passes through x axis at origin =ax^2 f'(x)=2ax f'(-2)=2(-2)a=1 a=-1/4 therefore f(x)=-1/4x^2
W Wonder Member Joined May 11, 2012 Messages 101 Gender Female HSC 2014 Jul 3, 2012 #3 Got it, thanks for your help! Last edited: Jul 3, 2012
W Wonder Member Joined May 11, 2012 Messages 101 Gender Female HSC 2014 Jul 3, 2012 #4 Wait, confused again. How did you get f(x)=2ax?
RealiseNothing what is that?It is Cowpea Joined Jul 10, 2011 Messages 4,591 Location Sydney Gender Male HSC 2013 Jul 3, 2012 #5 Wonder said: Wait, confused again. How did you get f(x)=2ax? Click to expand... He differentiated, it's f'(x) not f(x).
Wonder said: Wait, confused again. How did you get f(x)=2ax? Click to expand... He differentiated, it's f'(x) not f(x).
W Wonder Member Joined May 11, 2012 Messages 101 Gender Female HSC 2014 Jul 3, 2012 #6 Oh, right! Thanks.
