process of formation of polyvinylchloride and polystyrene. (2 Viewers)

[girlworld_club]

i can't seem to find the answers in any textbook.

 

[albertcamus]

Pretty sure its same as polyethylene but just replace the hydrogen with the chlorine atom and benzene ring respectively.

So initiation, propagation, termination.

 

[hayabusaboston]

Pretty sure its same as polyethylene but just replace the hydrogen with the chlorine atom and benzene ring respectively.

So initiation, propagation, termination.

Yea its the same, but to replace a hydrogen with chlorine atom and benzene ring involves extra process of a substitution reaction, before u start the polymerisation.

 

[girlworld_club]

does it use the same radical?

 

[albertcamus]

Yea its the same, but to replace a hydrogen with chlorine atom and benzene ring involves extra process of a substitution reaction, before u start the polymerisation.

Yep yep, but I think you can start off with the actual monomer as being Styrene/Vinyl Chloride

 

[albertcamus]

does it use the same radical?

Yep cos Peroxide radical's used because it has an unpaired electron I think which makes it more reactive

 

[hayabusaboston]

Yep cos Peroxide radical's used because it has an unpaired electron I think which makes it more reactive

benzoyl peroxide is the common one innit? It has easy to break O-O bond for reactive radicals

 

[albertcamus]

benzoyl peroxide is the common one innit? It has easy to break O-O bond for reactive radicals

Yeah you use it for that reason and then you split the peroxide molecule up into 2 peroxide radicals - each reacts with separate monomers and they propagate and eventually collide with each other in the termination reaction and form the polymer AFAIK.

 

[hayabusaboston]

Yeah you use it for that reason and then you split the peroxide molecule up into 2 peroxide radicals - each reacts with separate monomers and they propagate and eventually collide with each other in the termination reaction and form the polymer AFAIK.

Yes, and then the initiator molecule is engulfed by the reaction and so is no longer present at termination!
We are a good team! finishing each others sentences! lol

 

[girlworld_club]

lol, you guys are funn-ay. i wish i could take part.

 

[albertcamus]

Yes, and then the initiator molecule is engulfed by the reaction and so is no longer present at termination!
We are a good team! finishing each others sentences! lol

Hahaha (Y)

 

[Makematics]

why do we even need to know this?

 

[girlworld_club]

apparently it was asked in a past cssa paper.

 

[albertcamus]

why do we even need to know this?

It's an 'application' of your knowledge of LDPE production apparently...