Progress Logbook (NO OFF TOPIC PLS) (18 Viewers)

[scaryshark09]

i can 14bii and you said you get 15bii

 

[scaryshark09]

its so easy lol ur stupid (i didn't get full marks on that i messed it up in the exam)

ok i wont help you with 14 then

 

[synthesisFR]

i can 14bii and you said you get 15bii

they literally used like a sentence to explain it

 

[synthesisFR]

ok i wont help you with 14 then

i was literally joking pls help im so bad at inequality

look, I understand that it's a cute saying, but consider what that means in the context of adoption

?

 

[SadCeliac]

?

look at the entire post and maybe you'll understand the joke xx

 

[scaryshark09]

it makes sense

1 + x^2 >= 2x

therefore

(1 + x^2)/y + (1 + y^2)/x >= 2x/y +2y/x

= 2 (x/y + y/x)
>= 2 (2)
=4

for the end part, you need the inequality (x/y +y/x >= 2)

 

[synthesisFR]

look at the entire post and maybe you'll understand the joke xx

when i press the thing up it takes me to this post

 

[synthesisFR]

it makes sense

1 + x^2 >= 2x

therefore

(1 + x^2)/y + (1 + y^2)/x >= 2x/y +2y/x

= 2 (x/y + y/x)
>= 2 (2)
=4

i dont get this bit where is this coming from

 

[scaryshark09]

i dont get this bit where is this coming from

cause you use the first line that i wrote

1 + x^2 >= 2x
and
1 + y^2 >= 2y

 

[synthesisFR]

i dont get this bit where is this coming from

OH NVM
thats so demented why did they do that
they jsut divided both inequality b Y and added
i was trying to do like the am gm of TWO by adding (1 + x^2)/y + (1 + y^2)/x and got >= something else

 

[SadCeliac]

look, I understand that it's a cute saying, but consider what that means in the context of adoption

when i press the thing up it takes me to this post

broski.... look at the whole post I sent

 

[scaryshark09]

how do you do 16biii !!!???

 

[synthesisFR]

broski.... look at the whole post I sent

im so confused

 

[carrotsss]

i dont get 16biii at all !!!

you just repeatedly use the formula from (ii) to reduce the 2l to zero, then flip it using ur knowledge from (i) so that you can repeat the process to reduce 2k to zero, then convert things into double factorials and use the formula from (a) and algebra to get to the answer

 

[its_ace21]

broski.... look at the whole post I sent

i dont think he cares

 

[carrotsss]

you just repeatedly use the formula from (ii) to reduce the 2l to zero, then flip it using ur knowledge from (i) so that you can repeat the process to reduce 2k to zero, then convert things into double factorials and use the formula from (a) and algebra to get to the answer

i got it wrong though bc i messed up like one tiny part of the reduction of 2k

 

[scaryshark09]

you just repeatedly use the formula from (ii) to reduce the 2l to zero, then flip it using ur knowledge from (i) so that you can repeat the process to reduce 2k to zero, then convert things into double factorials and use the formula from (a) and algebra to get to the answer

"you just"
you're making it sound easy bruh

 

[synthesisFR]

cause you use the first line that i wrote

1 + x^2 >= 2x
and
1 + y^2 >= 2y

thats straightforward okay

i was trying to do something else then i got to

(xy+1)/y + (xy+1)/x >= 4
but i couldn't move on

idk yeah but it makes sense to use the part before
I need to revise inequality so much

 

[carrotsss]

"you just"
you're making it sound easy bruh

in fairness the question did say to use the previous parts

 

[synthesisFR]

if someone could help me visualise mcq for 7
and explain
15bii
and 16c
would be nice