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proj motion qn (1 Viewer)

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since u know that 0< sin(theta) < 1 since 0<theta<pi/2 , u can just put the expression for sin(theta) into the inequality. normally to solve the inequality u would multiply both sides by 14T but yk that T > 0 so u can just multiply everything by T without worrying about the sign switching.
 

Average Boreduser

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since u know that 0< sin(theta) < 1 since 0<theta<pi/2 , u can just put the expression for sin(theta) into the inequality. normally to solve the inequality u would multiply both sides by 14T but yk that T > 0 so u can just multiply everything by T without worrying about the sign switching.
I tried that and got 7 on rhs but lhs I get sqrt (147/5)
 

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