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I tried that and got 7 on rhs but lhs I get sqrt (147/5)since u know that 0< sin(theta) < 1 since 0<theta<pi/2 , u can just put the expression for sin(theta) into the inequality. normally to solve the inequality u would multiply both sides by 14T but yk that T > 0 so u can just multiply everything by T without worrying about the sign switching.
AAAnnnddd I just realised they baited me..... bruh these neap papers are acc so weird omds. Like its always the tiniest crap they catch u up on lmfao.I tried that and got 7 on rhs but lhs I get sqrt (147/5)