Q (1 Viewer)

[=)(=]

shouldnt the answer be A?

 

[synthesisFR]

wait is this nsg 2023

 

[=)(=]

yesss

 

[carrotsss]

there’s absolute value signs, so flip everything above the x axis to replace everything below. then, the domain of this new thing is the range of g(|x|)

 

[synthesisFR]

this paper ruined my life i was so close to getting 70/70 for the first time in my life and then this question came along

 

[=)(=]

this paper ruined my life i was so close to getting 70/70 for the first time in my life and then this question came along

lmao

 

[=)(=]

there’s absolute value signs, so flip everything above the x axis to replace everything below. then, the domain of this new thing is the range of g(|x|)

ohh ic ic but then wouldn't it no longer have an inverse fucntion, like it would fail the HLT

 

[carrotsss]

ohh ic ic but then wouldn't it no longer have an inverse fucntion, like it would fail the HLT

nope, try draw it, it still passes the HLT fine

 

[Luukas.2]

View attachment 40726
shouldnt the answer be A?

No, the answer B is correct.

Sketch the inverse by reflecting the given graph in y = x. That's g(x)

g(|x|) is the same as g(x) for x > 0... this starts at (0, a) and decreases to (d, b)... but g(|x|) is also even, so g(|x|) starts at (-d, b), rises to a y-intercept of (0, a), then decreases back to (d, b). Its domain is [-d, d] and its range is [b, a].