Yes, 100%.So do you agree with my answers?
ahh, I got 16 T_TThat's right iirc.
Probably because the question asked for degrees..damn for angle abc i put 33 degrees and the minutes following! will i lose a mark?
Technically you didn't do everything the question asked, so I wouldn't say it's unreasonable for losing a mark there.That's sucks, I would be inclined to think not though. I obviously showed all working and showed I could find the angle correctly, I shouldnt get marked down for having a more specific answer
Q 13 C)
Two buckets each contain red marbles and white marbles. Bucket A contains 3 red and 2 white marbles. Bucket B contains 3 red and 4 white marbles.
Chris randonly chooses one marble from each bucket
i) what is the probablility that both marbles are red
ii) what is the probability that at least one of the marbles are red
iii) what is the probability that both marbles are the same colour
My answers:
i) 9/35
ii) 26/35
iii) 9/35 +8/35 = 17/35
i agree with the answers sghguos got.Hi, here is the solution:
Bucket A: (3 Red, 2 White)
Bucket B: (3 Red, 4 White)
Let:
RA = A red marble from bucket A
WA = A white marble from bucket A
RB = A red marble from bucket B
WB = A white marble from bucket B
(i) Chris chooses a marble from each bucket.
P(both are Red) = P(RA AND RB)
= P(RA) AND P(RB)
= P(RA) x P(RB)
= 3/5 x 3/7
= 9/35
(ii)
P(at least one is Red) = 1 - P(none of the two are red)
= 1 - P(both are White)
= 1- P(WA AND WB)
= 1 - (2/5 x 4/7) = 1 - 8/35
= 27/35
ALTERNATIVELY:
P(at least one is Red)
= P(RA AND WB) OR P(WA AND RB) OR P(RA AND RB)
= (3/5 x 4/7) + (2/5 x 3/7) + (3/5 x 3/7)
= (12 + 6 + 9) / 35
= 27/35
(iii)
P(both are same colour)
= P(both are Red) OR P(both are White)
= P(RA AND RB) + P(WA AND WB)
= (3/5 x 3/7) + (2/5 x 4/7)
= 9/35 + 8/35
= 17/35
How do you get 26/35? Please show your working.i agree with the answers sghguos got.
ii) should be 26/35 not 27/35, its a 1 mark question should be an indicator that it is just a simple subtraction
ye.. u didnt put the 1 on the other side to make it negative 1, just u get.. 6/5 and 7/5.. like me ..oh shit.....
l got 6/5 and 7/5 for the coordinates of N
damn...
l lost 3 marks
so that's 14 definite marks gone. l don't think l can get band 5 now
P(At least one marble is white) = 1 - P(All Red)How do you get 26/35? Please show your working.
I guess it's sghguos's fault as they posted the (ii) of this question wrong!! (See below in bold)P(At least one marble is white) = 1 - P(All Red)
which is then 1 - 9/35 = 26/35
Originally Posted by sghguos
Q 13 C)
Two buckets each contain red marbles and white marbles. Bucket A contains 3 red and 2 white marbles. Bucket B contains 3 red and 4 white marbles.
Chris randonly chooses one marble from each bucket
i) what is the probablility that both marbles are red
ii) what is the probability that at least one of the marbles are red
iii) what is the probability that both marbles are the same colour[\QUOTE]
I answered the question as posted by sghguos.
But for the question as asked in HSC Mathematics 2012, you are correct, the answer is 26/35!!