Q14 in multiple choice?? (1 Viewer)

The Bograt

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I said D, the most reactive element will oxidise (go into solution) and is the anode
1. x<Pb
2. Pb<y
3. Pb<z
4. y<z
You need to use you potential values for the last one to see that they both use Pb, and so z must have a higher voltage potential or something and so

put them together you get x<Pb<y<z
That's how I did it anyway, don't know if it is 100% right
 

chelseafan

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bograt u ordered them in increasing reactivity.
the question asks for increasing ease of oxidation.
The more reactive the metal is the easier it will oxidise
that means that z,y,Pb,x is the answer, A
 

Aerials

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fcuk!!! i didnt read the question properly... "increasing ease of oxidation of the metals"...should have been D
 

chelseafan

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boutfiddy said:
my reasoning was:
negative terminal is the anode where oxidation occurs so from standard table of reductions x has reduction potential of 0.22 V and oxidising potential of -0.22 V. from same sort of thing y has oxidation potential of 0.97 and z has 2.47 so puting them in increasing order gives d
The question asks "Increasing EASE OF OXIDATION"
you have interepreted the question incorrectly.
The more reactive the metal, the easier it will oxidise!
So as oxidation occurs at the negative terminal then and this is where the more reactive metal is. Ordering the metals by increasing reactivity, which is what you have done! gives D. But this is not the question, it asks for increasing ease of oxidation, ie) from most reactive to least reactive. Giving A, the answer
 

chelseafan

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fuckin can sum1 argue their point!!
YOU all say the answer is D but u give false reasoning and some of u dont even fukin give a reason at all like this dickhead

xxxcaixxx said:
The "answer" is D....if they ask reduction. The answer is A
so sure about it without giving an explanation, what a wanka
 

KungPow

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From increasing ease: As you progress forward, it becomes easier to oxidise. So you would start from the one with lowest oxidation potential, and then go upwards. Thus, it should be D.

Hope that made sense. If not, er...it's too late now anyways. No point arguing.
 

chelseafan

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ok answer this... which is easier to oxidise gold(unreactive) or iron(more reactive)... ie) what is easier to achieve gold oxide or iron oxide?? Then u will understand the answer to this question
 

sub

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Hangon...ppl are saying diff shit...is it A or D??? pls one last time.
 

boutfiddy

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chelseafan04 said:
ok answer this... which is easier to oxidise gold(unreactive) or iron(more reactive)... ie) what is easier to achieve gold oxide or iron oxide?? Then u will understand the answer to this question
isn't iron easier to oxidise which means increasing ease of oxidation would be less reactive to more reactive
 

KungPow

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boutfiddy said:
isn't iron easier to oxidise which means increasing ease of oxidation would be less reactive to more reactive
Exactly what i was trying to say.
 

tennille

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x is clearly the least reactive one in comparison to lead. Then it is lead, because when it is compared to y or z, it is less reactive. So you are left with z and y. You could prolly distinguish them somehow but since you know the first two, the answer is D.
 

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