Q14 in multiple choice?? (2 Viewers)

[The Bograt]

I said D, the most reactive element will oxidise (go into solution) and is the anode
1. x<Pb
2. Pb<y
3. Pb<z
4. y<z
You need to use you potential values for the last one to see that they both use Pb, and so z must have a higher voltage potential or something and so

put them together you get x<Pb<y<z
That's how I did it anyway, don't know if it is 100% right

 

[scruffy012]

i think a i put

i dunno but the exam was good

scruffy

 

[sub]

hey hey i got it right...if its A...

 

[chelseafan]

bograt u ordered them in increasing reactivity.
the question asks for increasing ease of oxidation.
The more reactive the metal is the easier it will oxidise
that means that z,y,Pb,x is the answer, A

 

[aim54x]

d it was 4 me. i kinda thought that was right. readin these make u think bout ur own answers carefully don't they???

 

[Aerials]

fcuk!!! i didnt read the question properly... "increasing ease of oxidation of the metals"...should have been D

 

[chelseafan]

my reasoning was:
negative terminal is the anode where oxidation occurs so from standard table of reductions x has reduction potential of 0.22 V and oxidising potential of -0.22 V. from same sort of thing y has oxidation potential of 0.97 and z has 2.47 so puting them in increasing order gives d

The question asks "Increasing EASE OF OXIDATION"
you have interepreted the question incorrectly.
The more reactive the metal, the easier it will oxidise!
So as oxidation occurs at the negative terminal then and this is where the more reactive metal is. Ordering the metals by increasing reactivity, which is what you have done! gives D. But this is not the question, it asks for increasing ease of oxidation, ie) from most reactive to least reactive. Giving A, the answer

 

[chelseafan]

fuckin can sum1 argue their point!!
YOU all say the answer is D but u give false reasoning and some of u dont even fukin give a reason at all like this dickhead

The "answer" is D....if they ask reduction. The answer is A

so sure about it without giving an explanation, what a wanka

 

[KungPow]

From increasing ease: As you progress forward, it becomes easier to oxidise. So you would start from the one with lowest oxidation potential, and then go upwards. Thus, it should be D.

Hope that made sense. If not, er...it's too late now anyways. No point arguing.

 

[chelseafan]

ok answer this... which is easier to oxidise gold(unreactive) or iron(more reactive)... ie) what is easier to achieve gold oxide or iron oxide?? Then u will understand the answer to this question

 

[sub]

Hangon...ppl are saying diff shit...is it A or D??? pls one last time.

 

[sub]

thanks for that...really helped. no harshness intended

 

[boutfiddy]

ok answer this... which is easier to oxidise gold(unreactive) or iron(more reactive)... ie) what is easier to achieve gold oxide or iron oxide?? Then u will understand the answer to this question

isn't iron easier to oxidise which means increasing ease of oxidation would be less reactive to more reactive

 

[KungPow]

isn't iron easier to oxidise which means increasing ease of oxidation would be less reactive to more reactive

Exactly what i was trying to say.

 

[tennille]

yes, that's right.

 

[Managore]

then what's the answer? A or D?

 

[tennille]

It should be D. Is this question 14?

 

[The Bograt]

Yes, it is D

 

[Managore]

Buggery fuck... there goes my HSC

 

[tennille]

x is clearly the least reactive one in comparison to lead. Then it is lead, because when it is compared to y or z, it is less reactive. So you are left with z and y. You could prolly distinguish them somehow but since you know the first two, the answer is D.